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Step 1. Write the structure of the products side by side with their oxygen atoms pointing towards each other.

Step 2. Remove the oxygen atoms and join the two ends by a double bond, the structure of the alkene 'A' is

3.38. In a period, metallic character decreases as we move from left to right. Therefore, metallic character of K, Mg and Al decreases in the order: K > Mg > Al. However, within a group, the metallic character, increases from top to bottom. Thus, Al is more metallic than B. Therefore, the correct sequence of decreasing metallic character is: K > Mg > Al > B, i.e., option (d) is correct

1.43 There is one octahedral hole for each atom in hexagonal close packed arrangement. If the number of oxide ions (O2−) per unit cell is 1, then the number of

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Disclaimer: This information is sourced from the official website and may vary.

RRB Group D answer key is released online within few days after the exam is conducted. Candidates can download their answer keys by logging with the reqquired credentials. Candidates can also raise objections against the answer keys. The answer keys are not made available offline. Candidates need to download it online only.

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3.37.  (d) is incorrect.

1.42 The ratio less than 2:1 in Cu₂O shows that some cuprous (Cu⁺) ions have been replaced by cupric (Cu+2) ions. To maintain electrical neutrality, every two Cu⁺ ions will be replaced by one Cu⁺² ion, thereby creating a hole. As conduction will be due to the presence of these positive holes, hence it is a p -type semi conductor

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(a) Isomers of C₄H₈ having one double bond are:

(a) 2-Methykbuut-2-ene

(b) Pent-1-ene-3-yne

(c) But-1,3-diene

(d) 4-Phenylbut-1-ene

(e) 2-Methyl phenol (f) 5- (2-Methylpropyl)decane

(g) 4-Ethyldeca-1,5,8-triene

Chlorination of methane is a free radical reaction which occurs by the following mechanism involving initiation, propagation and termination steps:

From the above mechanism, it is evident that during the propagation step, CH₃ free radicals are produced, which may undergo three reactions, i.e., (i), (ii) and (iii). In the chain termination step, the two CH₃ free radicals combine to form ethane (CH₃—CH₃) molecule.

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