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Candidates seeking course admission at JD Institute of Fashion Technology Bangalore cannot enrol for direct admission. The college admits students based on merit. Candidates can apply online on the official website of the institute. Aspirants need to fill out the form, upload documents and pay the application fee to apply for admission.

Yes, Bunts Sangha's Ramanath Payyade College of Hospitality Management Studies provides summer internship opportunities to its students. Check out the table below to know more about the number of students placed during Bunts Sangha's Ramanath Payyade College of Hospitality Management Studies summer internships:

The PSNA College of Engineering and Technology provides excellent placement opportunities. For more information on placement highlights for the PSNA College of Engineering and Technology placements 2023-2025, refer to the table below:

In 2025, 40 companies were part of Bunts Sangha's Ramanath Payyade College of Hospitality Management Studies placement session. The table below states the same:

Course wise placements for Bunts Sangha's Ramanath Payyade College of Hospitality Management Studies has not been released yet. However, students can refer to the key highlights of the Bunts Sangha's Ramanath Payyade College of Hospitality Management Studies placement statistics given in the table below:

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (B), (C)

0.1 mole H₂SO₄ reacts with 1 mole of NaOH.

0.1 mole of NaOH will react with $\frac{0.1}{2\mathrm{}\mathrm{}}$ = mole of H₂SO₄

Here, NaOH is the limiting reagent.

2 mole of NaOH produces 1 mole of Na₂SO₄

0.1 mole of NaOH will give $\frac{0.1}{2\mathrm{}\mathrm{}}$  mole of Na₂SO₄

No. of mole = $\frac{\mathrm{g}\mathrm{i}\mathrm{v}\mathrm{e}\mathrm{n}\mathrm{}\mathrm{m}\mathrm{a}\mathrm{s}\mathrm{s}}{\mathrm{m}\mathrm{o}\mathrm{l}\mathrm{a}\mathrm{r}\mathrm{}\mathrm{m}\mathrm{a}\mathrm{s}\mathrm{s}\mathrm{}\left({\mathrm{N}\mathrm{a}}_2{\mathrm{S}\mathrm{O}}_4\right)\mathrm{}\mathrm{}\mathrm{}}$

On substituting the value in the above equation, the mass can be calculated as

0.05 mol = $\frac{\mathrm{g}\mathrm{i}\mathrm{v}\mathrm{e}\mathrm{n}\mathrm{}\mathrm{m}\mathrm{a}\mathrm{s}\mathrm{s}}{142\mathrm{}{\mathrm{g}\mathrm{}\mathrm{m}\mathrm{o}\mathrm{l}-}^1\mathrm{}\mathrm{}\mathrm{}\mathrm{}}$

given mass = 7.10 g

Volume of solution after mixing is 2 L.

So, the molarity of Na₂SO₄ is

Molarity = $\frac{0.05}{2\mathrm{}\mathrm{}\mathrm{}\mathrm{}}$  = 0.025mol L^-1

Candidates looking for course admission at JD Institute of Fashion Technology, Brigade Road cannot enrol for direct admission. JD Institute of Fashion Technology, Brigade Road admission to courses is based on merit. Candidates looking for course admission must have to complete Class 12 for the UG and graduation for the PG programme. 

The table below presents the average package recorded during the Bunts Sangha's Ramanath Payyade College of Hospitality Management Studies placements 2025:

Various companies visit Bunts Sangha's Ramanath Payyade College of Hospitality Management Studies for placements some of them are given below:

Yes, the University of Mannheim accepts scholarship applications from Indian students. Students from India are eligible to apply to most scholarships at the Uni Mannheim. This includes the Mannheim Scholarship, Opportunity Mannheim Scholarship & the Deutschland Scholarship among others. 

Here is how you can get 100% scholarship in Germany.

PSNA College of Engineering and Technology has released its placement details on its official website. For more information on placement packages and recruiters for the PSNA College of Engineering and Technology placements, refer to the table below:

The average package for Bunts Sangha's Ramanath Payyade College of Hospitality Management Studies stood at INR 2.5 LPA. Check the below table to know more about the average package at Bunts Sangha's Ramanath Payyade College of Hospitality Management Studies:

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (B)

In a, c, and d options given reactions, all the elements are balanced and hence, following the law of conservation of mass.

In reaction (B), C₃H₈+ O₂→ CO₂+H₂0  elements are not balanced. Hence product are different. It is against the law of conservation of mass