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5 months agoContributor-Level 7
The VITEEE 2026 dates have been announced online at viteee.vit.ac.in. Online registrations are open till March 31, 2026, and exam is tentatively scheduled between April 28 to May 3, 2026.
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5 months agoContributor-Level 10
Velocity of bird = v
Velocity w.r.t. observer in water = (4/3)v; 12 = 4 + (3/4)v ⇒ v = 6 cm/s
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5 months agoContributor-Level 7
No, candidates can book their exam slot during the slot booking phase. Candidates can access slot booking facility at OTBS portal. Once slot is booked, it cannot be reviewed or changed.
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5 months agoContributor-Level 7
No, VITEEE admit card will be available online only. Once the admit card is generated, students can download it from VITEEE login using their application number and password.
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5 months agoContributor-Level 7
VITEEE photo and signature specifications can be checked below-
| VITEEE document specifications | Details | File size and dimensions |
|---|---|---|
| Photograph | Candidate's photo must be clear, with white background. It must be in JPEG format. | File size: 20 to 300 kb Dimensions: width (300 to 400 pixels) X height (400 to 550 pixels) |
| Signature | Signature must be scanned properly and drawn inside box of size 6 cm (width) x 2 cm (height) on A4 paper. | File size: 5 kb to 150 kb Dimensions: 3.5 cm (width) x 1.5 cm (height) |
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5 months agoContributor-Level 10
The SITEEE syllabus for mathematics includes all the topics of the CBSE board for classes 11th and 12th.
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5 months agoContributor-Level 7
No. The VITEEE application form will not be available offline. Candidates who want to take admissions at VIT Group of Institutions must apply online and submit form before due date. VITEEE registration last date is March 31.
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5 months agoContributor-Level 10
Energy of products = 939 + 940 = 1879
ΔE + E_reactions – E_productor = 1877 – 1879 = -2MeV.
Hence it must capture a γ - ray photon of energy 2MeV.
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5 months agoContributor-Level 7
Yes, VIT offer scholarships to top rank holders of VITEEE. The scholarship details can be checked below -
| Performance in VITEEE exam | Scholarship details |
|---|---|
| VITEEE rank holders of 1 to 10 | 100% tuition fee waiver for all four years |
| VITEEE rank holders of 11 to 50 | 75% tuition fee waiver for all four years |
| VITEEE rank holders of 51 to 100 | 50% tuition fee waiver for all four years |
| VITEEE rank holders of 101 to 500 | 25% tuition fee waiver for all four years |
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5 months agoContributor-Level 10
f? = f? (330/ (330-V) f? = f? (330/ (330+V)
(f? - f? )/f? × 100 = 2% ⇒ (330/ (330-V) - (330/ (330+V) = 0.02
⇒ 330 [ (2V)/ (330)²-V²)] = 0.02 ⇒ 330V = 0.01 × (330)² ⇒ V = 3.3 m/s (approx.)
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5 months agoContributor-Level 7
With the help of VITEEE mock test, students will get to know about the VIT BTech exam pattern and difficulty level. Also, attempting mock test will improve time management and accuracy.
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5 months agoContributor-Level 7
Candidates can select only one VITEEE test city/exam centre at the time of filling the application form. They can only choose the test city that is listed from native state or current address or school state.
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5 months agoContributor-Level 7
The GATE provisional and final answer key are different. The GATE provisional answer key is released along with the response sheet. Through the provisional answer key, candidates will be able to raise objections. On the other hand, the final answer key is basically released after the review process, which is used for the GATE score evaluation. Candidates must note that the final answer key cannot be rechecked or raised for objections.
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5 months agoContributor-Level 10
(K (4A)/l) (100 – θ) = (KA/l) (θ – 50)
⇒ 400 – 4θ = θ – 50 ⇒ 5θ = 450 ⇒ θ = 90°C
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5 months agoContributor-Level 7
For VITEEE admissions, there is no specific reservation criteria. Students will be offered admission based on their rank, order of preferences, eligibility and seats.
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5 months agoContributor-Level 7
Dates for VITEEE seat allotment 2026 will be updated soon. The tentative counselling start date is 2nd week May 2026. There will be 5 rounds of counselling and students will have to register to participate.
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5 months agoContributor-Level 10
v? = 3tî v? = 24cos 60°î + 24sin 60°? = 12î + 12√3?
v? = v? – v? = (12 – 3t)î + 12√3?
It is minimum when 12 - 3t = 0 ⇒ t = 4sec
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