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BArch and BDes are both great options and are different mostly in terms of their overall focus. While BArch is all about architecture- designing buildings, planning spaces, and working on construction projects, a BDes course will focus on the more creative side of design. It covers a wide range of design fields, such as graphic, product, fashion, etc. Choosing a course will depend on your interest, aptitude, and aspiration.

No credentials are required for taking VITEEE mock test. Students can use dummy credentials to access. The mock test link will be made available on official website. Students will just have to select their stream and practice accordingly.

Vibrational energy of a non-rigid gas molecule is K? T so, total energy = (5/2)K? T + K? T = (7/2)K? T
∴ C? = (7/2)R

  $\tau ={\displaystyle \int F.r={\displaystyle \underset{0}{\overset{R}{\int }}\eta \left(2\pi rdr\right)\left(\frac{rw}{t}\right).r}}$  

  $=\frac{2\pi \eta W{R}^4}{4t}=\frac{2\times 3.14\times 1\times 8\times 10^{-4}}{4\times 2\times 10^{-3}}$          f

  $=0.625N-m?0.63N-m$            

VITEEE mock test will be available in the first week of March 2026. Students can visit official website and access to demo test. With this, students will get familiar with exam pattern and question paper difficulty.

Gain in K.E. $=$ $$ Loss in P.E.

${}_{}$  $K_p=eV$ for proton

$$ $K_{\alpha }=2\mathrm{e}\mathrm{V}$  for $$ $\alpha$ - particle

Again, Loss in K.E. $=$  $$ Work against field

${}_{}$ $K_p=eE\cdot S_0$  for proton

$\Rightarrow \mathrm{}eV=eE{S}_0$

$\therefore \mathrm{}{S}_0=\frac{V}{E}$

$$ $K_{\alpha }=2eE.S$  for $\alpha -$ $$ particle

$\Rightarrow \mathrm{}2eV=2eES$

$\therefore \mathrm{}S=\frac{V}{E}=S_0$

VIT will open VITEEE mock test link in March 2026. Students can attempt mock test without any login credentials. With the help of demo test, candidates will be able to figure about exam instructions, time limit, pattern, and question paper difficulty. Also, students must note that mock test for VIT entrance exam is for practice only, no scorecard will be generated for this.

Dedicate at least one to two months to VITEEE revision. The best way to revise for VITEEE exam is to make concepts clear. 

• Start with NCERT. Solve each question (that you find important)
• Look for the most repeated questions in VITEEE previous year's and solve them. Doing this will build accuracy and improve time management.
• Attempt PYQs and do not neglect English and Aptitude sections. Give equal importance to them as well.
• For any doubt, try asking mentors, friends, seniors or teachers and get your queries answered.
• Do a quick review at the end of the day to check your performance and progress.

tan 60° = (2kλ? /y? )/ (2kλ? /x? )

(√3λ? /x? ) = (λ? /y? ); √3λ? y? = λ? x?

The GATE admit card has details regarding the exam and the applicant like name, photo, signature, GATE paper code, exam date and time, centre code, guidelines, etc. Candidates must check details carefully before printing. If there is any discrepancy, applicants must immediately contact GATE helpline number. 

  $\frac{1}{2}m{V}_a^2-\frac{GMm}{2x}$  

           =   $\frac{1}{2}m\frac{V_a^2}{4}-\frac{GMm}{4x},\boxed{V_a=\sqrt[]{\frac{2}{3}\frac{GM}{x}}}$

ROC at point – B

$ROC=\frac{V_b^2}{a\perp }=\frac{\frac{2GM}{3R}\times \frac{1}{4}}{\frac{GM}{{\left(4R\right)}^2}}=\frac{8R}{3}$

v = √ (GM/r) (orbital speed)
⇒ GM = v²r ⇒ (GM/R²) = (v²r/R²) ⇒ g = (v²r/R²)

VITEEE syllabus covers topics and chapters from mathematics/biology, physics, and chemistry taught in classes 11 and 12th. VIT has provided the syllabus details in brochure based on which questions will be asked in VITEEE. With the help of the exam syllabus, students will be able to figure out topics they are good at and topics that needs special attention. Also, understanding syllabus can help students to mark high-weightage VITEEE chapters and prepare accordingly.

d = Rsin 60°

⇒ d = (mv√3)/ (qB 2) = (√3v)/ (2aB)

The complete SITEEE exam syllabus is important. However, students must pay extra attention to a select few topics of the SITEEE physics syllabus like Kinematics, Laws of Motion, Work, Energy, and Power, Gravitation, Thermodynamics, Oscillations and Waves, Electrostatics, Current Electricity, Magnetism, Electromagnetic Induction, Optics (Ray and Wave), the Dual Nature of Radiation and Matter, Atoms and Nuclei, and Semiconductors.

$V=\sqrt[]{\frac{\gamma RT}{M}},\mathrm{}$  where,  $T=T_1+\frac{T_2-T_1}{d}x$ ${}_{}\frac{{}_{}{}_{}}{}$

Also, $v=\sqrt[]{\frac{\gamma R273}{M}}\Rightarrow \sqrt[]{\frac{\gamma R}{M}}=\frac{v}{\sqrt[]{273}}$ $\text{exception 25:}\text{exception 25:}\frac{}{\text{exception 25:}}$

Also, $\mathrm{}V=\frac{dx}{dt}=\sqrt[]{\frac{\gamma RT}{M}}$ $\Rightarrow \mathrm{}{\int }_0^d?\frac{dx}{\sqrt[]{T_1+\frac{T_2-T_1}{d}x}}=\sqrt[]{\frac{\gamma R}{M}}{\int }_0^t?dt$ $\mathrm{}\frac{}{}\text{exception 25:}$

$\Rightarrow \mathrm{}t=\frac{\sqrt[]{273}}{v}\cdot \frac{2d}{T_2-T_1}\left(\sqrt[]{T_2}-\sqrt[]{T_1}\right)\mathrm{}\therefore \mathrm{}t=\frac{2d}{v}\frac{\sqrt[]{273}}{\sqrt[]{T_1}+\sqrt[]{T_2}}$

AP EAMCET Rank Card is released by the APSCHE. Rank Card will include the rank obtained by the student in the Andhra Pradesh EAMCET 2026 exam. It is an important document for Andhra Pradesh EAMCET Counselling and admission process. 

N = (mg/√2) + (mω²h/√2)
(mω²h/√2) = (mg/√2) + f?
(mω²h/√2) = (mg/√2) + μ (mg/√2) + (mω²h/√2)
ω = √ (g/h) (1+μ)/ (1-μ) = 10rad/s