Ask & Answer: India's Largest Education Community

1000+ExpertsQuick ResponsesReliable Answers

Need guidance on career and education? Ask our experts

Characters 0/140

The Answer must contain atleast 20 characters.

Add more details

Characters 0/300

The Answer must contain atleast 20 characters.

Keep it short & simple. Type complete word. Avoid abusive language. Next

Your Question

Edit

Add relevant tags to get quick responses. Cancel Post




Ok

All Questions

New Question

11 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

9.13. When hydrogen is burnt in oxygen the reaction is highly exothermic, it produces very high temperature nearly 4000°C which is used for cutting and welding purposes.

New Question

11 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

9.12. Metallic hydrides are useful for ultra-purification of dihydrogen and as dihydrogen storage media. In metallic hydrides, hydrogen is adsorbed as H-atoms. Due to the adsorption of H atoms the metal lattice expands and become unstable. Thus, when metallic hydride is heated, it decomposes to form hydrogen and finely divided metal. The hydrogen evolved can be used as fuel.

New Question

11 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

11.61 

In ortho nitrophenol there is intra-molecular H bonding, whereas in para-nitrophenol there is inter-molecular H bonding, as shown below:

And because of that para-nitrophenol get tightly bounded with water and ortho nitrophenol is steam volatile and it will leave the solution.

New Question

11 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

9.11. Those hydrides which do not have fix composition are called non-stoichiometric hydrides, and the composition varies with temperature and pressure. This type of hydrides is formed by d- and f-block elements. They cannot be formed by alkali metals because alkali metal hydrides form ionic hydrides.

New Question

11 months ago

0 Follower 2 Views

S
Sreetama Shrivastava

Contributor-Level 9

Yes, you will see reservations and quota systems for categories like EWS (Economically Weaker Sections), SC (Scheduled Castes), ST (Scheduled Tribes), OBC (Other Backward Classes), etc., in the Communication Design course admission. These reservations may vary depending on the course level and the college.

New Question

11 months ago

0 Follower 3 Views

A
Aayush Sharma

Contributor-Level 10

MMU Sadopur BSc admission takes place through merit secured in Class 12. Candidates applying for admission in MMU Sadopur BSc will have to have to attain a passing grade in Class 12 exams. Once results are announced, they can apply for BSc admission through their Class 12 score. Candidates will have to pay some amount of the tuition fees to secure their seat in MMU Sadopur BSc.

New Question

11 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

11.60

The different forms of cresol is formed with given molecular formula:

2-methylphenol

3-methylphenol

4-methylphenol

New Question

11 months ago

0 Follower 11 Views

A
alok kumar singh

Contributor-Level 10

11.58

The hydroboration-oxidation reaction is a two-step reaction that converts an alkene into a neutral alcohol by the net addition of water across the double bond. The hydrogen and hydroxyl group are added in a syn addition leading to the cis configuration. Hydroboration- oxidation is an anti-Markovnikov reaction, with the hydroxyl group attaching to the less substituted carbon. In first step Addition of Hydroborate group is done and in next step, it is oxidized by hydrogen peroxide.

For example: - When propene undergoes hydroboration-oxidation reaction, then it produces propan-1-ol as product. In this reaction diborane i.e., (BH3)2 re

...more

New Question

11 months ago

0 Follower 11 Views

A
alok kumar singh

Contributor-Level 10

11.57 

Due to the presence of –OH group, alcohols form hydrogen-bonds with water but hydrocarbons cannot form hydrogen-bonds with water.

Due to inter moleculer hydrogen bonding between Alcohol and water molecular they remain tightly bounded to water molecules and have higher solubility. Whereas in case of hydrocarbon there is no chance of hydrogen bonding.

New Question

11 months ago

0 Follower 7 Views

L
Liyansha Katariya

Contributor-Level 10

GITAM School of Technology Hyderabad is one of the renwoned institute which offers quality education to the students. The institute has been accredited with an “A+” Grade by the NAAC and recognised by the UGC and AICTE. The institute offers extensive course curriculum under the guidance of experts with years of experience.  GITAM School of Technology Hyderabad is collaborated with various industry partners. The institute has a well-equipped infrastructure which includes classrooms, a library, a cafeteria, labs, wifi campus, transport, a hostel and offers many facilities to the students.

New Question

11 months ago

0 Follower 5 Views

J
Jiya Khanna

Contributor-Level 9

The fees for 4-year BTech in Sapthagiri NPS University range from INR 8 Lacs to INR 11 lakh. Once candidates are shortlisted based on their entrance exam scores, candidates are required to appear for the physical verification of academic documents and admission fee payment before the last scheduled dates. The course fee might include multiple fee components, which are required to be paid once or semester-wise. 

NOTE: This information is sourced from the official website/ sanctioning body and is subject to change. 

New Question

11 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

11.56

Here, propanol undergoes intermolecular H-bonding because of the presence of -OH group while butane has no such property

(intermolecular Hydrogen bonding in propanol)

Therefore, extra energy will be required to break those hydrogen bonds which in turn causes higher boiling point for propanol when compared to butane.

New Question

11 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

9.10. Carbon hydrides of the type CnH2n+2 are electron precise hydrides. Because they have atom with exact number of electrons to form covalent bonds. Thus, they do not behave as Lewis acid or base. Since they have no tendency to accept or lose electrons.

New Question

11 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

9.9. It is expected to be a Lewis acid. They are likely to accept electrons to become stable. They can form coordinate bond with electron rich compound.
                                    2NaH(s) + B2H6 (g) → 2Na+[BH4]-  (s)

                                        

...more

New Question

11 months ago

0 Follower 2 Views

New Question

11 months ago

0 Follower 1 View

H
Himanshi Pandey

Contributor-Level 10

Candidates willing to pursue a BSc (Hons) at Navrachana University can apply for admission in online mode. The university accepts online registrations for admission through its official website. Candidates must visit the university's official website when the admission window is open. They must click on 'Apply now' displayed on the homepage. On the redirected page, they can fill out the registration form. While doing so, they must select their desired BSc specialisations. The application process is incomplete without submitting the prescribed application fee. 

New Question

11 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

9.8.  (i) Electron deficient hydrides: Compounds in which central atom has incomplete octet, are called electron deficient hydrides. For example, BeH2, BH3 are electron deficient hydrides.

(ii) Electron precise hydrides: Those compounds in which exact number of electrons are present in central atom or the central atom contains complete octet are called precise hydrides e.g., CH4, SiH4, GeH4 etc. are precise hydrides.

(iii) Electron rich hydrides: Those compounds in which central atom has one or more lone pair of excess electrons are called electron rich hydrides, e.g., NH3, H2O.

New Question

11 months ago

0 Follower 9 Views

Shiksha Ask & Answer
Tasneem Hoda

Contributor-Level 10

Shiksha has ranked Monash University streams such as Engineering, Nursing, and Medicine & Health Sciences with top rankings. Some of the top course rankings at the university are given as follows:

Course Name Shiksha Popularity Ranking Quacquarelli Symonds Rank 
MS#4#4
Mathematics #4#78
MBA/PGDM#5#84
MS in Nursing #2#24

New Question

11 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

11.55 

The structures of all isomeric alcohols of C5H12O are given below:

Naming is done by the conventional method. The -OH group is attached on the first carbon.

(b) 3-Methylbutan-1-ol

Butane is the longest chain and methyl is the substituent group.

(c) 3-Methylbutan-1-ol

the longest chain is butane and conventional naming method is used.

(d) 2,2-Dimethylpropan-1-ol

Isomer is made by transforming the principal carbon into tertiary type. The longest chain is butane and named accordingly.

(e) Pentan-2-ol

the longest chain is pentane and the numbering is chosen from the minimum position.

(f) 3-Methylbutan-2-ol

Butane is the longest chain,

...more

New Question

11 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

9.7. This is due to its small atomic size and small bond length (74 pm) of H-H bond.H? H bond has very high bond enthalpy (435.9 kJ/mol) which results in low reactivity at room temperature. The reactivity is increased at high temperature or in presence of catalyst. Under these conditions, hydrogen reacts with many metals and non-metals to form hydrides.

Register to get relevant
Questions & Discussions on your feed

Login or Register

Ask & Answer
Panel of Experts

View Experts Panel

Share Your College Life Experience

×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.