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6 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Data is not sufficient but official answer is (D)

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6 months ago

0 Follower 20 Views

P
Parul

Beginner-Level 4

Yes, you can easily get in touch with Chandigarh University for detailed information about the CSE branch. The official contact number for any kind of guidance is 1800121288800 and students can call it anytime during working hours. Apart from the helpline, the university also provides admission counselors who guide you about eligibility, courses, and fee structure. Another option is to fill out the online enquiry form on the Chandigarh University website, after which a counselor will call you directly. Visiting the campus in person is another great way, so that you can visit the CSE department and directly interact with faculty members

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6 months ago

0 Follower 18 Views

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Gagan Hansra

Beginner-Level 5

For B.E in CSE, Chandigarh University is really amazing and placement rate is 100%. The placements are top- notch as MNCs like Google, Accenture, Deloitte, HP, Flipkart, Wipro, and Samsung visit the campus. CU trains students from day one through its Career Planning and Development Department (DCPD) with resume building, mock interviews, GDs, and more. Each department has also a placement coordinator and faculty support to guide students. The university has tie-ups and collaborations with KPIT, Capgemini, Virtusa, IBM, Oracle, Intel, and CISCO etc.

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6 months ago

0 Follower 21 Views

S
Sukhpreet Singh

Beginner-Level 3

Chandigarh University has seen strong placements for its CSE students with Robotics and AI specialisation. The course connects both software and automation fields, which opens more job options. Students get placed in big IT firms, research companies, and technology startups. Companies like Amazon, Deloitte, Infosys, and SAP Labs often recruit from the university. Many students also get training and internship offers that later turn into full-time jobs. The placement drive includes both national and international companies offering competitive packages. CU provides dedicated placement training, coding tests, and mock interviews which he

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6 months ago

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6 months ago

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S
sam

Beginner-Level 4

Everyone has mixed reviews, so don't just go by what you see online. I would like to clarify that Chandigarh University does not offers B.Tech in CSE, it offers B.E. in CSE, which is way better. It has accreditations from the Accreditation Board for Engineering and Technology (ABET) and the National Board of Accreditation (NBA). This means the degree is valued not just in India but all over the world. The dept has advanced labs like the Microsoft Innovation Centre, IBM Software Lab and Virtusa Robotics & Automation Center. Students get to work on real-time projects and learn through workshops, seminars and expert sessions. Learning nev

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6 months ago

0 Follower 18 Views

K
Kartik Wadhwa

Beginner-Level 3

Candigarh University offers many choices in CSE, not just the regular Computer Science program. Students can pick specialisations in trending fields like Artificial Intelligence & Machine Learning, Data Science, Cyber Security, Cloud Computing, Blockchain, Robotics & AI, Internet of Things (IoT), and Full Stack Development. These programs are co-designed with industry leaders like IBM, Microsoft, Virtusa, and Oracle, so the course content stays updated with the latest technology. Each specialisation also comes with certification opportunities and hands-on training in dedicated labs. For example, in CSE with AI & ML, students work on re

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6 months ago

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R
Raj Pandey

Contributor-Level 9

λ e = h P e = h 2 m e K e λ e 2 = h 2 2 m e k e K e = h 2 2 m e λ e 2 - (i)

λ P = h P P = h c K P K P = h c λ P - - (ii)

              Ke = KP

λ P α λ e 2

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6 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Moles of PCl5 = 5 mol

Moles of Ar = 4 mol

Total no of moles = 9 moles

P T o t a l = n R T V = 9 × 0 . 0 8 2 1 × 6 1 0 1 0 0 = 4 . 5 a t m  

P P C l 5 = X P C l 5 × P T = 5 9 × 4 . 5 = 2 . 5 a t m  

P A r = X A r × P T = 4 9 × 4 . 5 = 2 a t m  

P C l 5 ? P C l 3 + C l 2  

2.5                       0            0                          

2.5 - P                 P            P

P T o t a l = 2 . 5 P + P + P + P A r = 6  

P = 1.5

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6 months ago

0 Follower 17 Views

A
Alisha Gupta

Beginner-Level 4

Scoring an 8+ CGPA in Chandigarh University's CSE branch is not too hard if you stay regular with classes and practice coding. The faculty here actually supports students a lot with doubt-clearing sessions and extra tutorials before exams. Most of the subjects are designed in a way that mixes theory with practical projects, so if you attend labs and complete assignments on time, half the work is already done. CU also provides online resources, mock tests, and open-book quizzes, which makes it easier to prepare. The exam evaluation is fair, and internal marks like quizzes and class tests boost your overall grade. Many students who balan

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6 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

Resolving power, = d 1 . 2 2 λ = 2 4 . 4 × 1 0 2 1 . 2 2 × 2 4 4 0 × 1 0 1 0  

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6 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Species =            CH4                       N H 4 +                     B H 4 ?  

Electrons =         10                        10

 

 

New Question

6 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

 At minimum deviation –

δ = 2 i A i = δ + A 2 , r = A 2  

Using snell’s low : -         s i n i = μ = s i n r  


δ + A 2 = π A 2 δ = π 2 A  

New Question

6 months ago

0 Follower 11 Views

B
Bandi Venkata Yaswanth

Beginner-Level 2

Yes, definitely but you have to pay donation amount chosen by the University 

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6 months ago

0 Follower 19 Views

New Question

6 months ago

0 Follower 21 Views

N
Nidhi Singh

Contributor-Level 6

Chandigarh University's CSE programme stands out because it gives students both strong academic learning and practical industry exposure. The curriculum is designed in such a way that it keeps changing with new technology trends. Students don't just study theory; they get real-time learning through labs, live projects, and workshops. The university focuses a lot on skill-based education. There are regular seminars, coding challenges, and guest lectures from experts who work in the tech field. What makes it even better is the environment — it motivates students to learn more, explore, and innovate. The CSE department also encourages r

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6 months ago

0 Follower 16 Views

N
Nidhi saxena

Beginner-Level 4

In the CSE (Hons.) programme at Chandigarh University, the academic schedule is carefully planned to combine rigrous learning with personal flexibility. The programme has around 160 credits including lectures, lab lessions, and projects. Typically students attend five to six classes a day which also includes practical sessions in specialised labs such as IBM software lab for emerging technologies, Microsoft lab, or red hat lab. Despite the structured schedule, students get free time in the evenings and on weekends. The balance between academics and free time helps students focus on skill enhancement without feeling overoaded. Since the

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New Question

6 months ago

0 Follower 20 Views

S
Shilpee

Contributor-Level 6

In the recent placement season, Chandigarh University saw 3750 engineering students getting selected. More than 240 companies came to campus and this count grew by 30 perscent from the last year. There was also a 70 percent rise in core branch companies, which showed more interest in fresh students. The total offers increased by 60 percent which showed that many firms wanted to hire more students. Around 500 companies gave packages above 5 LPA and more han 100 companies offered above 10 LPA. Students even reached an international packages of 1.7 crore and a national package of 54.75 LPA. The numbrs speak in a vry simple way and make th

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6 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

E 0 = 2 . 2 5 v m Speed of declromagnetic signal, v = E 0 B 0 = 2 . 2 5 v / m 1 . 5 × 1 0 8 T  

    B 0 = 1 . 5 × 1 0 8 T v = 2 2 5 1 5 0 × 1 0 8 = 1 . 5 × 1 0 8 m / s  

Time to reach each to the same

radar,   t = 2 × 3 × 1 0 3 m 1 . 5 × 1 0 8 m / s = 4 × 1 0 5 S  

New Question

6 months ago

0 Follower 15 Views

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