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It is a covalent chemical bond that connects amino acids to form polypeptide chains.

According to kepler’s third law of time period –

  ${\left(\frac{T_A}{T_B}\right)}^2={\left(\frac{r_A}{r_B}\right)}^3\Rightarrow \frac{r_A}{r_B}=4^{1/3}$  

$\Rightarrow r_4^3=4r_B^3$  

Different functions of biomolecules include storing genetic information (by nucleic acids), providing energy (by carbohydrates), and building and repairing tissue (by proteins).

Use formula for M.I.

$x=4sin\left(\frac{\pi }{2}-\omega t\right)$  - (i)

$y=4sin\left(\omega t\right)$   - (ii)

From (i) and (ii) cos^{2 $\omega t+si{n}^2\omega t={\left(\frac{x}{4}\right)}^2+{\left(\frac{y}{4}\right)}^2=1$}

$\Rightarrow x^2+y^2={\left(4\right)}^2$  

For 2S, number of radial moles = $n-\mathcal{l}-1=2-0-1=1$ and ${\Psi }^2\left(r\right)$  will always be positive

$\therefore option\left(B\right)iscorrect?$ it has one radial node and it is positive.

a = k2rt2

$\Rightarrow \frac{v^2}{r}=k^{2}r{t}^2$

$\Rightarrow v=krt$

$a_t=\frac{dv}{dt}=kr$

? tangential force, F_t = ma_t = mkr

$\therefore Powerdelivered,P=F_{t}v=\left(mkr\right)\left(krt\right)=m{k}^2{r}^{2}t$  

 Note ® Power delivered by centripetal force will be zero.

Kindly go through the solution 

 $\frac{0.02858*0.112}{0.5702}=0.0561$

Since current is in phase with voltage, it means circuit is in resonance, so we can write

f =  $\frac{1}{2\pi \sqrt[]{LC}}=\frac{1}{2\pi \sqrt[]{\left(0.5\times 10^{-3}\right)\times \left(200\times 10^{-6}\right)}}$  

$\Rightarrow f=\frac{10^4}{2\pi \sqrt[]{10}}\approx 5\times 10^{2}Hz$         $\left[Taking\pi =\sqrt[]{10}\right]$  

According to Young’s double slit experiment, we can write

$\beta =\frac{\lambda D}{d}\Rightarrow \Delta \beta ={\beta }_2-{\beta }_1=\frac{\lambda }{d}\Delta D$

$\Rightarrow \lambda =\frac{d\Delta \beta }{\Delta D}=\frac{1\times 10^{-3}\times 3\times 10^{-5}}{5\times 10^{-2}}=60\times 10^{-8}m=600nm$

According to Nuclear activity, we can write

$N_0\stackrel{t_{\frac{1}{2}}}{\to }\frac{N_0}{2}\stackrel{t_{\frac{1}{2}}}{\to }\frac{N_0}{4}\stackrel{t_{\frac{1}{2}}}{\to }\frac{N_0}{8}\stackrel{t_{\frac{1}{2}}}{\to }\frac{N_0}{16}=\left(0.0625\right)N_0$  

Time required = 4 ×  $t_{\frac{1}{2}}=20yrs$

According to question, we can write

$\mathcal{l}=2\pi r\Rightarrow r=\frac{\mathcal{l}}{2\pi }$  

$I_1=\frac{m{\mathcal{l}}^2}{3},and{I}_2=\frac{m{r}^2}{2}=\frac{m{\mathcal{l}}^2}{8{\pi }^2}$

$\Rightarrow \frac{I_1}{I_2}=\frac{m{\mathcal{l}}^2}{3}\times \frac{8{\pi }^2}{m{\mathcal{l}}^2}=\frac{8{\pi }^2}{3}$

According to definition of displacement current, we can write

$I_d={\epsilon }_0\frac{d?}{dt}={\epsilon }_0\frac{d\left(ES\right)}{dt}={\epsilon }_0\frac{d\left(\frac{V}{\mathcal{l}}S\right)}{dt}=\frac{{\epsilon }_{0}S}{\mathcal{l}}\left(\frac{dV}{dt}\right)$  

$\Rightarrow \mathcal{l}=\frac{8.85\times 10^{-12}\times 40\times 10^{-4}\times 10^6}{4.425\times 10^{-6}}8\times 10^{-3}m$  

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The TS PGECET 2026 question paper will contain a total of 120 questions, which are objective-based. For each correct answer, one mark will be awarded. However, there is no negative marking for the incorrect responses. Candidates are advised to check the TS PGECET pattern carefully before preparing for the exam. 

Firstly, understand your strengths and weaknesses, then focus on the fundamentals, create a personalized study plan, set realistic goals, effective study techniques.

Reporting time has been divided into 3 shifts which starts from 8.30 AM, 12.00 PM and 3.00 PM.

Yes, the CUET (Common University Entrance Test) for postgraduate (PG) programs typically includes specific time slots or schedules for different courses or disciplines.

An SOP is your personal account of your motivations, interests, aspirations and experiences. While you may go through a few samples, it is advisable to write the first draft by yourself and then fine-tune it in terms of the writing style and verbiage. Ensure to convey your story and make sure to include things that you could not elaborate on in your resume.