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Candidates can check the JEECUP answer key through their candidate login portal using their application number and password.

kindly consider the following Image 

CoCl₃.NH₃ + AgNO₃ $\stackrel{}{\to }AgC\mathcal{l}\downarrow \left(2mol\right)$

$\left[Co{\left(N{H}_3\right)}_{5}C\mathcal{l}\right]C{\mathcal{l}}_2+AgN{O}_3\stackrel{}{\to }AgC\mathcal{l}\downarrow \left(2mol\right)$  

x = 5

kindly consider the following Image 

$M{n}^{2+}\stackrel{}{\to }{t}_{2g^{111}}{e_g}^{11}$

(Number of unpaired electron = 5)

${\mu }_S=\sqrt[]{35}=5.91\cong 6$

Kindly consider the following Image

$K=A.e^{-Ea/RT}=\left(6.5\times 10^2\right)e^{-26000K/T}$  

$\frac{Ea}{8.314}=26000$

E_a = 216.164kJ/mol $\cong$ 216

No, it doesn't change. The National Testing Agency (NTA) has been consistently responsible for conducting the Common University Entrance Test (CUET) PG since its inception.

In thin layer chromatography, the spots of colourless compounds, which are invisible to eyes can be detected by putting the plate under UV light.

Another detection technique is to place the plate in a covered jar containing I₂ (s). Sometimes an appropriate reagent may also be sprayed on the plate, ninhydrin in case of amino acids.

Undergraduate courses offered at IHMs are as follows:

• BSc in Hospitality and Hotel Administration (HHA)

• BA in Culinary Arts

• BSc in IT

• BSc Computer Science

Although there are many other courses taught in IHMs India, however, these courses are very popular among Central IHMs, State IHMs, and Private IHMs.

DDT, organophosphates and dieldrin are pesticides.

H₂ (g) + Cu²⁺ (aq) $\stackrel{}{\to }$  2H⁺ (aq) + Cu (s)

$\therefore E_{cell}=E_{cell}^0-\frac{2.303RT}{nf}logQ$  

0.31 = 0.34 -  $\frac{0.06}{2}log\frac{\left[H^{+}\right]}{C{u}^{2+}}$  

$\left[C{u}^{2+}\right]=10^{-7}\left(?\left[H^{+}\right]=10^{-3}\right)$  

x = 7

There is a total of 71 Institutes of Hotel Management that is IHMs in India. The number includes both Central Government-sponsored IHMs and State Government-sponsored IHMs.

The JEECUP result will comprise the candidate's name, roll number, marks obtained and the rank secured in the exam.

$\Delta T_b=i{K}_{b}m$

$\Delta T_f=i{K}_{f}m$

$\therefore \frac{4}{4}=\frac{K_b\times 1.5}{K_f\times 4.5}$

$\frac{K_b}{K_f}=3$

${\left[Ni{\left(CN\right)}_4\right]}^{2-}$  

CN^- is strong field ligand

$N{i}^{2+}=4s^{0}3d^8$  

 Here; ${\left[Ni{\left(CN\right)}_4\right]}^{2-}$ is square planar and diamagnetic.

$\left[Ni{\left(CO\right)}_4\right]$  

Ni = 4s²3d⁸         Co is strong field ligand.

Here ;  $\left[Ni{\left(CO\right)}_4\right]$  is tetrahedral and diamagnetic

${\left[Ni{\left(CN\right)}_4\right]}^{2-}$  has 3d⁸ configuration while $\left[Ni{\left(CO\right)}_4\right]$  has 3d¹⁰ configuration.

The JEECUP result link will be updated on the official website, jeecup.admissions.nic.in. Candidates can check their JEECUP scores through the candidate login portal using their application number and password.

Moles of N₂O = $\frac{2.2}{44}=\frac{1}{20}$  

$\Delta H=n{C}_p\Delta T=\frac{1}{20}\times 100\left(-40\right)=-200J$  

$\Delta U=q_p+w$

$w=-P_{ext}.\Delta V$  

$w=-1\frac{\left(167.75-217.1\right)}{1000}\times 101.3J=+5J$  

$\Delta U=-200+5=195J$

The authority will announce the JEECUP 2026 result date online along with the exam notification.