Ask & Answer: India's Largest Education Community

$Mn{O}_2+4HCl\to MnC{l}_2+C{l}_2+2H_{2}O$

$\begin{array}{l}C{l}_2+2Kl\to 2KCl+I_2\\ I_2+2N{a}_2{S}_2{O}_3\to 2Nal+N{a}_2{S}_4{O}_6\end{array}$

Here, meq of MnO₂ = meq of Na₂S₄O₆

$\frac{w}{E}\times 1000=M\times n-factor\times V$

$\frac{w}{87/2}\times 1000=0.1\times 1\times 60$

Mass of MnO₂ in sample = 0.261 g

Percentage of MnO₂ in sample = $\frac{0.261}{2}\times 100$  

 = 13.05%

Yes, the Vellore Institute of Technology has released the VITREE application form 2026. Registration window was open on August 27 and last date to submit the application form is November 24 (extended). Candidates who are willing to take admission in PhD programmes in VIT can apply for VITREE exam. 

$\underset{\begin{array}{l}Sodiumextract\\ ofsulphur\end{array}}{N{a}_{2}S}+N{a}_2\underset{Sodiumnitroprusside}{\left[Fe{\left(CN\right)}_{5}NO\right]}\to N{a}_4\underset{violet/purple}{\left[Fe{\left(CN\right)}_{5}NOS\right]}$

First common term to both AP’s is 9

t₇₈ of $\left(3,6,9,......\right)=78\times 3=234$  

t₅₉ of $\left(5,9,13,........\right)=5+\left(5-1\right)4=237$  

n^th common term $\le 234$  

9 + (n – 1) 12   234

n <  $\frac{237}{12}\Rightarrow n=19$  

Now sum of 19 terms with a = 9, d = 12

$=\frac{19}{2}\left(2.9+\left(19-1\right)\cdot 12\right)=2223$  

Candidates have to carry their JEECUP admit card, a government ID proof, a black/blue pen for rough work and a transparent water bottle while appearing for the JEECUP exam.

$\alpha -$  Helix (2°) structure of protein is stabilized by intermolecular H-bonding.

$\frac{dy}{dx}+\frac{2x}{x-1}\cdot y=\frac{1}{{\left(x-1\right)}^2}$

IF  $=e^{{\displaystyle \int \frac{2x}{x-1}dx}}$  

=  $e^{2x}\cdot {\left(x-1\right)}^2$  

$y\cdot e^{2x}{\left(x-1\right)}^2=\{e^{2x}\frac{{\left(x-1\right)}^2}{{\left(x-1\right)}^2}dx+C$

y =  $\frac{e^{2x}}{2{\left(x-1\right)}^2}+\frac{C}{{\left(x-1\right)}^2}$  

y(2) =  $\frac{1+e^4}{2e^4},\Rightarrow C=\frac{1}{2}$  

y(3) =  $\frac{e^{\alpha }+1}{\beta e^{\alpha }}=\frac{e^6+1}{8e^6}$  

Data contradiction.

$\overrightarrow{a}\times \left(\overrightarrow{b}\times \overrightarrow{c}\right)=\left(\overrightarrow{a}\cdot \overrightarrow{c}\right)\overrightarrow{b}-\left(\overrightarrow{a}\cdot \overrightarrow{b}\right)\overrightarrow{c}$

Copolymer is the polymer formed by two or more monomers having multiple bonds.

Buna – S, PHBV and butadiene – styrene are copolymers. Neoprene is homopolymer.

Candidates can download the JEECUP 2026 admit card using their application number and password. Registered applicants will find the JEECUP admit card download link on the website, jeecup.admissions.nic.in.

$R-N{H}_2\underset{273K}{\overset{HN{O}_2\left(aq.\right)}{\to }}R-\stackrel{\oplus }{N_2}\underset{298K}{\overset{H_{2}O/-N_2\uparrow }{\to }}R-OH$

1° aliphatic amine           Diazonium salt                Alcohol

It is aldol condensation.

The authority will announce the JEECUP admit card release date in its official exam notification. Candidates will be able to download the JEECUP hall ticket from its release date until their exam date.

IIT JAM is for PG scientific and engineering courses in IITs and other premier institutons while CUET PG is a wider platform for admissions to postgraduate programs across private, state and central universities.

No. Students can only object to the provisional answer key of JEECUP. 

kindly consider the following Image 

Candidates can fill up to four cities as per their preferences in the CUET PG 2026 application form. Initially, two city choices could be entered, but later on, NTA increased the number to four for greater flexibility for students. 

The JEECUP answer key challenge fee is Rs 100 per answer challenged. Candidates can pay the answer key challenge fee in online mode through credit/debit cards or through netbanking.

kindly consider the following Image