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Siva Sivani Degree College Hyderabad (SSDCH), also known as SSDCH, is recognised by UGC and is approved by the AICTE. It is a prestigious college, located in Hyderabad, and offers various courses to students at the UG level in affiliation with Osmania University. SSDC Hyderabad is a member of the renowned SP Sampathy's Siva Sivani Group of Institutions. The college is mainly concerned with streams such as Business Management, Commerce, and Computer Applications. Apart from this, the college has a panel of guest lecturers to inspire students in their respective careers and to give them tips and invaluable insights in every course.

Mass, m = 14.5 kg

Length of the steel wire, l = 1.0 m

Angular velocity,  $\omega$ = 2 rev/s

Cross sectional area of the wire, A = 0.065 ${cm}^2$ = 0.065 $\times {10}^{-4}{m}^2$

Let Δl be the elongation of the wire

When the mass is placed at the position of the vertical circle, the total force on the mass is

F = mg + ml ${\omega }^2$ = 14.5 $\times \left(9.81+1\times 2^2\right)$ = 200.25 N

Young’s modulus for steel,  $Y_s$ = Stress / Strain = 2 $\times {10}^{11}$ Pa

Stress = F/A = 200.25/0.065 $\times {10}^{-4}$

Strain = (Δl/l) = (Δl/1) = Δl

Δl = (200.25/0.065 $\times {10}^{-4})/$ 2 $\times {10}^{11}$ = 1.54 $\times {10}^{-4}$ m

11.23 Wavelength produced by X-ray, $\lambda =$ 0.45 Å = 0.45 $\times {10}^{-10}$ m

Planck’s constant, h = 6.626 $\times {10}^{-34}$ Js

Speed of light, c = 3 $\times {10}^8$ m/s

The maximum energy of a photon is given as:

$E$ = $\frac{hc}{\lambda }$ = $\frac{6.626\times {10}^{-34}\times 3\times {10}^8}{0.45\mathrm{}\times {10}^{-10}}$ = 4.417 $\times {10}^{-15}$ J = $\frac{4.417\times {10}^{-15}}{1.6\times {10}^{19}}$ eV = 27.6 $\times {10}^3$ eV = 27.6 keV

Therefore, the maximum energy of an X-ray photon is 27.6 keV

To get an X-ray of 27.6 keV, the incident electrons must possess at least 27.6 keV of kinetic energy. Hence an accelerating voltage in the order of 30 keV will be required.

The total tuition fee for the BCom course at Nilamber Pitambar University ranges between INR 3,162 and INR 3,195. Additional costs such as admission fees, hostel charges, registration, and other one-time payments may apply. These figures are sourced from the university's official site and are subject to change, so students should verify current details before applying.

Yes, UG Diploma course is available at CII Institute of Hospitality - Hyatt Delhi. The institute offers UG Diploma courses is offered for 18 months. Candidate must meet the eligibility criteria to enrol for UG Diploma course admission set by the college. Aspirants must pass graduation. CII Institute of Hospitality - Hyatt Delhi's admission process is aptitude test.

It is given that the tension, F in each wire is same. Since the wire is of same length, Strain also will be same.

If $d_c$ is the diameter of copper wire and Young’s modulus of copper $Y_c$ = 110 $\times {10}^{9}Pa$ and strain is s, then $Y_c$ = $\frac{F}{\frac{\pi }{4}{d_c}^2}$ , $d_c=\sqrt{\frac{4F}{\pi \times Y_c}}$

Similarly, if $d_i$ is the diameter of iron wire and $Y_i$ is the Young’s modulus of iron = 190 $\times {10}^{9}Pa$ , then $d_i$ = $\sqrt{\frac{4F}{\pi \times Y_i}}$

$\frac{d_c}{d_i}$ = $\sqrt{\frac{Y_i}{Y_c}}$ = $\sqrt{\frac{190}{110}}$ = 1.314

Almost every student must had this thought of passing the WB 12th board exams without studying, however, one should understand that WBCHSE board exams are a turning point for their future. While there is no shortcut to pass the WB 12th board exams without studying, students can follow the points listed below and try their best to pass WB 12th board exams.

• Use Mind Maps And Visual Aids
• Compile All The Notes
• Practice Regular Summarisation
• Quiz Yourself
• Review Course Notes
• Use Online Resources
• Using A Tutor Or Study Group
• Use Mnemonics
• Stay Positive And Confident
• Prioritise Sleep and Nutritio

Area of cross-section, A = $\pi {1.5}^2$ ${cm}^2$ = 7.07 $\times {10}^{-4}{m}^2$

Maximum stress = Maximum load / cross sectional area

Maximum load = Maximum stress $\times$ cross sectional area = 108 $\times$ 7.07 $\times {10}^{-4}$ = 7.07 $\times {10}^4$ N

Following documents are required:

1. Class 10 marksheet
2. School leaving certificate 
3. Duly filled admission form 
4. FYJC admission Allotment Letter 
5. Passport size photo
6. Income certificate and caste certificate (if you are under any quota)

Candidates seeking admission to the MBA programme of MGKVP Varanasi may want to compare it with other universities offering the course. Such a comparison must be based on important parameters depending on the candidates' preferences and priorities. Candidates willing to compare MGKVP with other similar universities for an MBA can keep the following factors in mind:

• Location, Infrastructure and facilities 
• Course structure and curriculum
• Medium of language in which the course is being offered
• Fees, placements, ROI
• Selection Criteria/ Entrance Exams
• Rankings and accreditations
• Student reviews on all the aforementioned factors

Area of cross-section, A = 15.2 mm $\times 19.1\mathrm{m}\mathrm{m}$ = 15.2 $\times 19.1\times {10}^{-6}{\mathrm{m}}^2=2.9\mathrm{}\times {10}^{-4}{\mathrm{m}}^2$

Force, F = 44500 N

Stress, F/A = (44500/$2.9\mathrm{}\times {10}^{-4})$ N/ ${\mathrm{m}}^2$

Modulus of elasticity,  $\eta$ = Stress / Strains, Strains = Stress / $\eta$

For copper,  $\eta$ = 42$\times {10}^9$ $\mathrm{N}/{\mathrm{m}}^2$

Strains = (44500/$2.9\mathrm{}\times {10}^{-4})/($ 42 $\times {10}^9)$ = 3.65 $\times {10}^{-3}$

Yes, fulfilling the English language requirement is one of the major admission requirements for international students to study MBA in Europe. Students can refer to the table below for minimum IELTS scores required by the top universities:

To get admission in the UG Diploma course at CII Institute of Hospitality - Hyatt Delhi, students need to fulfill eligibility and selection criteria. A candidate scoring a minimum of 50% in Class 12 is eligible to apply for Diploma admission at the institute. Admission to this course is based on aptitude test.

While Nilamber Pitambar University requires candidates to meet the minimum eligibility and secure valid scores in CBSE 12th or JAC 12th exams, specific details about direct admission are not clearly mentioned. Typically, eligible candidates can apply directly if merit-based. It's advisable to visit the official university website or contact the admission office for accurate guidance.

Mass of the big structure, M = 50000 kg = 50000 $\times 9.8N$ = 4.9 $\times {10}^5$ N

Inner radius of the column, r = 30 cm = 0.3 m

Outer radius of the column, R = 60 cm = 0.6 m

Young’s modulus of steel, Y = 2 $\times {10}^{11}$ Pa

Total force exerted on 4 columns, F = 4.9 $\times {10}^5$ N

Force exerted on single column, f = F/4 = 1.225 $\times {10}^5$ N

Cross sectional area of each column, A = $\pi (R^2-r^2)$ = $\pi ({0.6}^2-{0.3}^2)$ = 0.848 $m^2$

Stress in each column = f/A

Young’s modulus, Y = Stress / Strain, Strain = Stress / Y = f/ (A $\times Y)$ = $\frac{1.225\mathrm{}\times {10}^5}{0.848\times 2\times {10}^{11}}=7.22\times {10}^{-7\mathrm{}}$ m

All those students are eligible to apply for JEST 2026 Exam who wish to pursue a PhD or integrated PhD in Theoretical Computer Science, Computational Biology, Physics, or Neuroscience. 

Edge of the aluminium cube, L = 10 cm = 0.1 m, Area A = 0.01 $m^2$

Mass attached, m = 100 kg = 100 $\times$ 9.8 = 980 N = Applied force F

Shear modulus $\eta$ = 25 GPa = 25 $\times {10}^{9}Pa$

Shear modulus $\eta$ = Shear stress / Shear strain = $\frac{\frac{F}{A}}{\frac{?L}{L}}$ ,  $?L=\frac{F\times L}{\eta \times A}$ = $\frac{980\times 0.1}{25\mathrm{}\times {10}^9\times 0.01}$ = 3.92 $\times {10}^{-7}m$