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Siva Sivani Degree College Hyderabad (SSDCH) is a private college and was established in 2002. It is also known as SSDCH and is located in Hyderabad, Telangana. The college is recognised by the UGC and is approved by the AICTE. SSDC Hyderabad is a member of the renowned SP Sampathy's Siva Sivani Group of Institutions.

Diameter of wires, d = 0.25 cm, radius, r = 0.125 cm

Cross-sectional area, $A_1$ = $A_2$ = $\pi \times r^2=0.049{cm}^2$ = 4.908 $\times {10}^{-6}$ $m^2$

Length of the steel wire, $L_1=1.5\mathrm{}\mathrm{m}$ , length of the brass wire, $L_2=1.0\mathrm{}\mathrm{m}$

Change in length of the steel wire $=?L_1,$ Change in length of the copper wire $=?L_2$

Total force exerted on the steel wire, $F_1$ = ( 4+6) kg = 10 kg = 98 N

Young’s modulus of steel , $Y_1$ = $\frac{\frac{F_1}{A_1}}{\frac{?L_1}{L_1}}$ = 2.0 $\times {10}^{11}$ Pa

$?L_1$ = $\frac{F_1}{A_1}\times \frac{L_1}{Y_1}=\mathrm{}\frac{98\times 1.5}{4.908\times {10}^{-6}\times 2.0\times {10}^{11}}$ = 1.497 $\times {10}^{-4}$ m

Similarly for brass wire, $F_2$ = 6 kg = 58.8 N, $Y_2$ = $0.91\times {10}^{11}\mathrm{}\mathrm{P}\mathrm{a}$

$?L_2$ = $\frac{F_2}{A_2}\times \frac{L_2}{Y_2}=\mathrm{}\frac{58.8\times 1.0}{4.908\times {10}^{-6}\times 0.91\times {10}^{11}}$ = 1.316 $\times {10}^{-4}$ m

To be eligible for the BCom programme at Nilamber Pitambar University, students must have completed their class 12 education from a recognised board. They must also have a valid score in the CBSE 12th or JAC 12th examinations. Meeting the minimum eligibility criteria is essential for consideration during the admission process.

For a given stress, the strain in rubber is more than it is in steel, hence the Young's modulus of rubber is lesser than in steel. So the statement is False.

Shear modulus is the ratio of the applied stress to the change in the shape of a body. The stretching of a coil changes its shape. Hence, shear modulus of elasticity is involved in this process.

 = 2.2 $*{10}^{-4}{m}^3$

The end date for students to complete the JEST 2025 Application Process is May 30, 2025, until 11:55 pm IST. The JEST Exam is conducted once a year and this year it is goig to be held on June 22, 2025. 

Material A has greater Young's modulus.

Material A is the strongest as it can withstand more strain than material B without fracture.

Yes, Nilamber Pitambar University (NPU) in Jharkhand offers a full-time, three-year Bachelor of Commerce (BCom) programme. The course is available in several specialisations such as Business Law, Auditing and Control, Tax Law, and Cost and Management Accounting. It is designed to provide students with foundational and specialised knowledge in commerce and finance-related subjects.

From the given graph, for the value stress 150 $*{10}^6$ N/ $m^2$ , the strain is 0.002

Young's modulus = $\frac{150\mathrm{}*{10}^6}{0.002}$ = 7.5 $*{10}^{10}$ N/ $m^2$

Yield strength is the maxium strength the material can withstand in elastic limit. From the graph, the yield strength is 300 $*{10}^6$ or 3 $*{10}^8\mathrm{N}/m^2$

University College of Commerce and Business Management MBA course is available across multiple specialisations including Finance, Human Resources Management, Marketing, and Information Systems. Candidate can choose any specialisation in the second year of the course.

Length of the steel wire, $L_1$ = 4.7 m

Area of cross-section of the steel wire, $A_1$ = 3.0 $\times {10}^{-5}$ m2

Length of the copper wire, $L_2$ = 3.5 m

Area of cross-section of the copper wire, $A_2$ = 4.0 $\times {10}^{-5}$ m2

Change in length, $\Delta {L=}_{}{L}_1-L_2$

Let the force applied = F

Young’s modulus in steel wire,

$Y_1$ = $\frac{F_1}{A_1}\times \frac{L_1}{\mathrm{\Delta }{L}_{}}$ ….(1)

Young’s modulus in copper wire,

$Y_2$ = $\frac{F_2}{A_2}\times \frac{L_2}{\mathrm{\Delta }{L}_{}}$ …….(2)

The ratio of Young’s modulus

$\frac{\mathrm{}{Y}_1}{Y_2}$ = $\frac{F_1}{A_1}\times \frac{L_1}{\mathrm{\Delta }{L}_{}}\times \frac{A_2}{F_2}\times \frac{\mathrm{\Delta }{L}_{}}{{\mathrm{L}}_2}$ = $\frac{L_1}{A_1}\times \frac{A_2}{L_2}$ = $\frac{4.7\times 4\times {10}^{-5}}{3\times {10}^{-5}\times 3.5}$ = $\frac{18.8}{10.5}=1.79$

Class 10th must be passed by any recognised board(Maths, English, science). Admission is merit based determined by your class 10 score. Obtain offline application form from college and full it out with required documents.

KIIT SOM has not yet released the placement data specifically for BBA. However, the institute's overall placement statistics are available for the year 2024. As per the data,  the the highest international and domestic packages bagged by the students participating in the 2024 placement drive stood at INR 18 LPA and INR 19 LPA, respectively. Apart from this, the average package offered to students stood at INR 9 LPA. 

CII Institute of Hospitality - Hyatt Delhi eligibility requires students to pass Class 12 with a 50% aggreagate with English as a compulsory subject. In addition to fulfilling the eligibility, students must also clear the aptitude test and Industry-Panel Viva to get shortlisted. Interested students can head over to the official website of the college for more information.

Yes, Pratibha Institute of Business Management )Kamala Education Society's) admissions are currently open. Interested students can visit the college's official website to get all the latest information about the course of choice. The institute accepts candidates primarily on an entrance basis, hence, students are advised to keep the exam scorecards, along with other documents as per the institute's guidelines.

To seek admission in a KIIT SOM BBA programme, a candidate must have completed Class 12 with at least 50% marks and Mathematics/Business Mathematics/Economics/Statistics as one of the subjects. Those who are eligible must further register for KIITEE conducted by KIIT and appear for the exam on the scheduled date. Once the exam is over, students must participate in the counselling process. Afterwards, students who are offered a seat must report to the institute for verification of documents and payment of fees. Successful fee payment completes the admission process.

Gian Jyoti Institute of Management & Technology is a popular institute with strong academic reputation, indutsry centric programme & career opportunities. The reasons to go for this college are:

• AICTE approval
• Good placements, etc

To know which institute is better for MBA, candidates can compare University College of Commerce and Business Management and  JNTU Hyderabad for its MBA course based on mutiple components. Find below the comparisons: 

CII Institute of Hospitality - Hyatt Delhi offers admissions mainly on the basis of an aptitude test followed by Industry Panel Viva based on which the seat is offered. Hence, no, the institute does not accept students on a direct basis. However, students interested in joining the institute may connect with the college via mail or phone to know more about the admission process and chances of getting into the course of choice.