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Sona Medical College of Naturopathy and Yoga provides a range of facilities for its students. It includes a central library, yoga halls, computer labs, modern laboratories, anatomy labs, gymnasium and hostels. The other facilities include opportunities to learn foreign languages, earn while studying and indoor and outdoor sports complex. 

Yes, you can get direct admission if you are already enrolled in a similar programme and have completed your first year without any backlog.

Yes, Motherhood University reserves seats for SC, ST, OBC and physically handicapped candidates (with a minimum disability of 40%) candidates as per the reservation policy made by the State Government under the Constitution of India or as notified by the Government of India. Besides, the university also reserves 40% of seats for the permanent residents of Uttarakhand. 

Your eyeglass prescription of –3.5 D is within the Army Nursing Assistant medical standards. The limit for myopia is –5.5 D (Nursing) and –3.5 D (General Army). If your vision can be corrected to 6/6 and you have normal color vision without serious eye conditions, you are considered medically fit for the post.

Motherhood University selects candidates for admission to most of the courses based on their qualifying exam scores. The university may also conduct an entrance exam to shortlist candidates for a few courses. Aspirants with a valid score in CAT or MAT are offered direct admission in the MBA course. Hence, the requirement of entrance exam depends on the course applied by the candidate for admission.

Yes, Jharkhand Raksha Shakti University offers both BSc and BSc (Hons) courses. The mode of study is full-time for all these programmes. Candidates can check below the list of offered courses:

• BSc (H) in Forensic Science
• BSc (H) in Computer Application & Cyber Security
• BSc in Nursing

Students must note that the mentioned course specialisations as per unofficial sources. The information may vary. Hence, is indicative. 

St. Clair College graduates work in top-notch companies such as Walmart, Ford Motor Company, University of Windsor, Walmart Canada, Stellantis, TD, and more. According to unofficial sources on the web, the average salary of St. Clair College graduate is CAD 70,000 (INR 43.45 LPA) annually.

34. Given, n = 100.

incorrect mean ( $\overline{x}$ ) = 20.

incorrect standard deviation (σ) = 3

We know that,

$\overline{x}=\frac{1}{n}{\displaystyle \sum _{i=1}^n{n}_i}$

$\Rightarrow 20=\frac{1}{100}{\displaystyle \sum _{i=1}^n{n}_i}$

$\Rightarrow {\displaystyle \sum _{i=1}^n{n}_i}=2000.$

So, incorrect sum of observation = 2000

Correct sum of observation $=2000-21-21-18$

= 1940

Jharkhand Raksha Shakti University (JRSU) select students for BSc/ BSc (H) admission on a merit-basis. The applicants performance in Class 12 or equivalent exam is evaluated for selection purposes. Moreover, the university may select students based on CUET scores as well. Apart from this, it is crucial that aspirants meet the eligibility criteria to secure a seat. 

33. C.V in mathematics = $\frac{12}{42}\times 100=28.57.$

C.V in Physics = $\frac{15}{32}\times 100=46.87.$

C.V in chemistry = $\frac{20}{40.9}\times 100=48.89$

$\therefore$  Chemistry has the highest variability and mathematics has the lowest variability.

32.  (i) Given, n = 20.

Incorrect mean $(\overline{x})=10$

Incorrect standard deviation $(\sigma )=2$

We know that,

$\overline{x}=\frac{1}{n}{\displaystyle \sum _{i=1}^n{x}_i}$

$\Rightarrow 10=\frac{1}{20}{\displaystyle \sum _{i=1}^{20}{x}_i}$

$\Rightarrow {\displaystyle \sum _{i=1}^{20}{x}_i}=200$

So, incorrect sum of observation = 200.

correct sum of observation =200 – 8 = 192

And correct mean $=\frac{192}{19}=10.1$

If you didn't score well in entrance exams but still want to do B.Tech in CSE, don't worry—many private colleges offer direct admission through management quota based on your 12th marks. Just make sure you meet the basic eligibility (usually 45–50% in PCM). Reach out to colleges directly and apply early for better chances.

31. For n observations x₁, x₂,……., x_n .

We have mean = $\overline{x}=\frac{{\displaystyle \sum _{i=1}^n{x}_i}}{n}\left(1\right)$

and variance = ${\sigma }^2=\frac{1}{n}{\displaystyle \sum _{i=1}^n{\left(x_i-\overline{x}\right)}^2\left(2\right)}$

Let y_i  be the new observations with same n.

So,  y_i = ax_i      (3)

Now mean, $\overline{y}=\frac{{\displaystyle \sum _{i=1}^n{y}_i}}{n}=\frac{{\displaystyle \sum _{i=1}^{n}a{x}_i}}{n}=\frac{a{\displaystyle \sum _{i=1}^n{y}_i}}{n}=a\overline{x}\left[\left(1\right)\right]$

So  $\overline{y}=a\overline{x}\left(4\right)$

And, putting (3) and (4) in (2) we get,

${\sigma }^2=\frac{1}{n}{\displaystyle \sum _{i=1}^n{\left(\frac{y_i}{a}-\frac{\overline{y}}{a}\right)}^2}$

$\Rightarrow {\sigma }^2=\frac{1}{a^2}\left[\frac{1}{n}{\displaystyle \sum _{i=1}^n{\left(y_i-\overline{y}\right)}^2}\right]$

$\Rightarrow {\left({\sigma }^{\text{'}}\right)}^2={\sigma }^2{\alpha }^2.$

Hence, the mean and variance of ax₁, ax₂, ……, ax_n  are $a\overline{x}$ and a² σ² .

30. Let 'x' be the given observations with n = 6.

Yes, admissions are open at Uttaranchal College of Science and Technology. Interested candidates can visit the official website and apply for the BSc cousre. Uttaranchal College of Science and Technology BSc admission is entirely merit-based. To get candidates just need Class 12 with 45% marks (SC/ST 40%) aggregate from a recognised board. There is are entrance exam required for BSc admission. Further, the college conducts interview rounds to shortlist candidates for final admission. 

Jharkhand Raksha Shakti University BSc course aspirants must be Class 12 or equivalent examination pass. The qualifying exam should have been passed with a minimum of 45% aggregate. Students must have the pass certificate with them during form filling and course admission. It must be noted that the mentioned minimum aggregate is as per unofficial sources. It is subject to changes and hence, is indicative.

For BTech admission, Karnavati University accepts JEE (Mains) and GUJCET scores. Candidates willing to secure admission based on their JEE (Main) ranks are required to clear the cut-off decided by the university for their preferred specialisation. the cut-off also varies across the reservation categories of the candidates. The following table presents the specialisation-wise Karnavati University BTech cut-off for the General (All India) category candidates in 2024: