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BA students at NEFTU can apply for scholarships based on academic merit, entrance exam ranks, economic background, and achievements in sports or arts. These scholarships offer tuition fee waivers ranging from 15% to 100%, helping students manage the financial aspects of their education.

This is a Long Answer Type Questions as classified in NCERT Exemplar

While you can't get a truly 0% interest education loan in India, there are government schemes that offer student loan interest-free periods. This means there are strategies that can help you significantly reduce the interest burden, effectively making your education more affordable.

This is a Long Answer Type Questions as classified in NCERT Exemplar

This is a Long Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}LetI={\displaystyle \int e^{ta{n}^{-1}x}}\left(\frac{1+x+x^2}{1+x^2}\right)dx\\ Putta{n}^{-1}x=t\Rightarrow \frac{1}{1+x^2}.dx=dt\\ ={\displaystyle \int e^t}\left(1+tant+ta{n}^{2}t\right)dt={\displaystyle \int e^t\left(se{c}^{2}t+tant\right)dt}\\ Here,f\left(t\right)=tant\\ \therefore f^{\text{'}}\left(t\right)=se{c}^{2}t\\ =e^t.f\left(t\right)=e^{t}tant=e^{ta{n}^{-1}x}.x+C\\ \left[?{\displaystyle \int e^t}\left[f\left(x\right)+f^{\text{'}}\left(x\right)\right]dx=e^{x}f\left(x\right)+C\right]\\ Hence,I=e^{ta{n}^{-1}x}.x+C\end{array}$

Indian Institute of Management offers both entrance-based and merit-based admissions. Candidates must fulfill the eligibility criteria for MBA programme admission. Find below eligibility, and selection criteria.

This is a Long Answer Type Questions as classified in NCERT Exemplar

This is a long answer type question as classified in NCERT Exemplar

(a) The weight of the body changes during oscillations.

(b) Considering the situations in two extreme positions

we can say mg-N= ma

so at the highest point the platform is accelerating downward.

N=mg-ma

a=w²A

N=mg-mw²A

A= amplitude of motion m=50kg v=2m/s

w=2 $\pi v=4\pi rad/s$

 A= 5cm = 5 $\times {10}^{-2}m$

N= 50 $\times 9.8-50\times {\left(4\pi \right)}^2\times 5\times {10}^{-2}=95.5N$

When it is accelerating towards mean position that is vertically upwards

N-mg=ma=Mw²A

N=mg+mw²A

N=m (g+w²A)

N= 50 [9.8+ ${\left(4\pi \right)}^2\times 5\times {10}^{-2}$ ]

N= 884N

Machine reads the normal reaction

Maximum weight =884N

Minimum weight=95.5N

This is a Long Answer Type Questions as classified in NCERT Exemplar

Cheran College of Nursing offers BSc Nursing and MSc Nursing courses. The selection criteria are based on merit. The application process at CCN conducted online. To secure a seat, students can check the following steps presented below:

Step 1: Visit the official website and complete the online application process. 

Step 2: Ensure eligibility and selection criteria for all programme.

Step 3: The selection criteria is based on merit.

Step 4: Upon selected, pay the specified fee to confirm and secure your seat.

Based on previous placement outcomes at North East Frontier Technical University, students from courses like BA have seen the highest salary package reach INR 6 LPA, while the average package has been around INR 3.5 LPA. These numbers reflect the overall placement results across the university's programmes.

This is a Long Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}LetI={\displaystyle \int \frac{x^2}{\left(x^2+a^2\right)\left(x^2+b^2\right)}}dx\\ Put{x}^2=tforthepurposeofpartialfraction.\\ Weget\frac{t}{\left(t+a^2\right)\left(t+b^2\right)}\\ Put\frac{t}{\left(t+a^2\right)\left(t+b^2\right)}=\frac{A}{t+a^2}+\frac{B}{t+b^2}\left[whereAandBarearbitrar\mathrm{yconstants}.\right]\\ \frac{t}{\left(t+a^2\right)\left(t+b^2\right)}=\frac{A\left(t+b^2\right)+B\left(t+a^2\right)}{\left(t+a^2\right)\left(t+b^2\right)}\\ \Rightarrow t=At+A{b}^2+Bt+B{a}^2\\ Comparingtheliketerms,weget\\ A+B=1andA{b}^2+B{a}^2=0\\ \Rightarrow A=\frac{-a^2}{b^2}B\\ \therefore \frac{-a^2}{b^2}B+B=1\\ B\left(\frac{-a^2}{b^2}+1\right)=1\Rightarrow B\left(\frac{-a^2+b^2}{b^2}\right)=1\\ \Rightarrow B=\frac{b^2}{b^2-a^2}andA=\frac{-a^2}{b^2}\times \frac{b^2}{b^2-a^2}=\frac{a^2}{a^2-b^2}\\ So,A=\frac{a^2}{a^2-b^2}andB=\frac{-b^2}{a^2-b^2}\\ \therefore {\displaystyle \int \frac{x^2}{\left(x^2+a^2\right)\left(x^2+b^2\right)}}dx=\frac{a^2}{a^2-b^2}{\displaystyle \int \frac{1}{x^2+a^2}dx-}\frac{b^2}{a^2-b^2}{\displaystyle \int \frac{1}{x^2+b^2}dx}\\ =\frac{a^2}{a^2-b^2}\times \frac{1}{a}ta{n}^{-1}\frac{x}{a}-\frac{b^2}{a^2-b^2}.\frac{1}{b}.ta{n}^{-1}\frac{x}{b}\\ =\frac{a}{a^2-b^2}ta{n}^{-1}\frac{x}{a}-\frac{b}{a^2-b^2}ta{n}^{-1}\frac{x}{b}+C\\ Hence,I=\frac{1}{a^2-b^2}\left[ata{n}^{-1}\frac{x}{a}-bta{n}^{-1}\frac{x}{b}\right]+C.\end{array}$

Yes, admissions at Cheran College of Nursing are open now. CCN offers admission to candidates based on merit. Aspirants also need to meet the eligibility criteria to apply for a course. Selected candidates are required to keep their educational documents ready for verification purposes.

The SICSR Pune offers placement opportunities to the MBA graduates every year. The average salary trends that were witnessed through SICSR Pune MBA placements over the last three years are as follows:

This is a Long Answer Type Questions as classified in NCERT Exemplar