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The total tuition fee charged by Ranchi University for BBA courses ranges from INR 25,500 to INR 45,000. This fee is given in a range because it varies from institute to institute.

Note: This fee has been sourced from official sources. However, it is subject to change. Hence, it is indicative.

Hi, BSc in Psychiatric Nursing is generally not offered in India. You'll need to complete a BSc Nursing (base course) after that you can pursue an MSc in Psychiatric Nursing. Here's a syllabus overview of BSc Psychiatric Nursing in colleges abroad:

Note: The information is sourced from external websites and may vary.

Yes, Baba Farid University of Health Science does offer seat reservation for the BSc course. The reservation of seats shall be as per the policy of the Government of Punjab. Moreover, the number of seats may be increased or decreased by the university and final
category wise seats will be calculated and displayed at the time of venue counselling.

Yes, students can pursue BBA at Ranchi University. This management course is only offered via colleges affiliated with the university. The key highlights of this course are tabulated below:

Note: The above information is taken from official sources. However, it is subject to change.

This is a long answer type question as classified in NCERT Exemplar

(a) velocity attained by a falling rain drop will be = $\sqrt[]{2gh}=\sqrt[]{2\times 10\times 1000}$

= $100\sqrt[]{2}m{s}^{-1}=\frac{510km}{h}$

(b) diameter of the rain drop = 2r=4mm

Radius = 2mm= 2 $\times {10}^{-3}m$

Mass of rain drop = V $\times \rho =\frac{4}{3}\pi r^3\rho =\frac{4}{3}\times \frac{22}{7}\times {\left(2\times {10}^{-3}\right)}^3\times {10}^3=3.4\times {10}^{-5}kg$

Momentum of rain drop= mv= 3.4 $\times {10}^5\times 100\sqrt[]{2}=5\times {10}^{-3}kgm/s$

(c) time ,t = d/v= $\frac{4\times {10}^{-3}}{100\sqrt[]{2}}=0.028\times {10}^{-3}s$

(d) force exerted, F = change in momentum /time=

(e) area = $\pi R^2=\pi \times {\frac{1}{2}}^2=\frac{11}{14}=0.8m^2$

number of drops striking the the umbrella with separation of 5 $\times {10}^{-2}$

so net force = $\frac{0.8}{{(5\times {10}^{-2})}^2}\times 168=53760N$

Baba Farid University of Health Sciences is affiliated with more than 75 colleges, and the total number of seats offered is around 4,367. From which one of the affiliated colleges offers the highest number of seats in the BSc course? Check out the name of the affiliated college with the number of offered seats in the table below:

In the case of Maya Academy of Advanced Creativity, Pitampura application process 2025, shortlisters should prepare vital documents. These are Class 10 and 12 marksheets, passport-size photo, Aadhaar Card and caste certificate in case of caste certificate. A slip form and bank challan copy with pay application fee are to be attached as well. All documents should be duly submitted in order to be eligible.

As per the available information, there is no provision for direct admission to the KK University's BTech course. Admission to the programme is based on the applicants' performance in the University Entrance Test conducted by the university. The entrance test may be followed by a GD and/or a PI. Additionally, applicants are required to fulfil the eligibility criteria specified by the university. Hence, direct admission is not possible at KK University for BTech.

This is a multiple choice answer as classified in NCERT Exemplar

(b, d) We know that one light year = 9.46 $\times {10}^{11}m$ = distance that light travels in 1 year with a speed 3 $\times {10}^8$ m/s

1 par sec =3.08 $\times {10}^{16}m$ = distance at which average radius of earth’s orbit subtends an angle of par second.

Here second and year represent time.

Maya Academy of Advanced Creativity, Pitampura does not demand any rank or entrance test scores to take admission. There is no reservation form and admissions are strictly on merit basis that is based on your Class 12th marks. In case you qualify, you can make your applications personally. It is straightforward, and selecting students is dependent on academic accomplishment only.

This is a multiple choice answer as classified in NCERT Exemplar

(a, b) we know that pressure = force/area

Pressure= $\frac{force\times distance}{area\times distance}=\frac{work}{volume}=\frac{energy}{volume}$

So we can say that pressure is also equal to energy per unit volume.

Yes, you can become a part of Maya Academy of Advanced Creativity, Pitampura immediately after Class 12. All the certificate programmes require only a percentage score of 50 in Class 12 as the basic requirement to get into the programme. The skill development is founded upon fresh school graduates admissions to the institute. Courses are designed to suit the creative students who are on their start-up career.

This is a multiple choice answer as classified in NCERT Exemplar

(a,b,d) h=[ML²T^-1]

[c]=[LT^-1], [m_e]=M

[G]= [M^-1L³T^-2]

[e]=[AT],[m_p]=[M]

[ $\frac{hc}{G}$ ] = $\frac{\left[M{L}^2{T}^{-1}\right]\left[L{T}^{-1}\right]}{M^{-1}{L}^3{T}^{-2}}=M^2$

M= $\sqrt[]{\frac{hc}{G}}$

$\frac{h}{c}=\frac{M{L}^2{T}^{-1}}{L{T}^{-1}}=\left[ML\right]$

L= $\frac{h}{cM}=\frac{h}{c}\sqrt[]{\frac{G}{hc}}=\frac{\sqrt[]{Gh}}{c^{3/2}}$

C= LT^-1

T= $\frac{\left[L\right]}{\left[C\right]}$ = $\frac{\sqrt[]{Gh}}{c^{3/2}c}=\frac{\sqrt[]{Gh}}{c^{5/2}}$

Hence a,b and d any can be used to express L,M and T in terms of three chosen fundamental quantities.

The final deadline of Maya Academy of Advanced Creativity, Pitampura 2025 admission is still not declared yet. It is recommended that students keep applying early to prevent last minute problems. The notifications can be checked on a regular basis on the official site. Applications are being taken up to the cut off in different courses.

Yes, IIM Calcutta is a famous college. The college has a renowned faculty with years of experience. The college is ranked 7th by NIRF 2025 under the Management category. Internationally, the IIMCal is ranked 50 by the QS World University Rankings 2024 - Masters In Management,  and 61-70 by the QS World University Rankings 2024 - Masters In Business Analytics.

This is a multiple choice answer as classified in NCERT Exemplar

(b, d) as we know E= hv

So h=E/v= $\frac{ML{T}^{-2}}{T^{-1}}$ =ML²T^-1

Dimension of linear impulse = dimensions of momentum= [MLT^-1]

As we know that J= $?p$

Angular impulse =tdt= $?L$ = change in angular momentum

Hence angular momentum is [ML²T^-1] same as the dimension of h.

This is a multiple choice answer as classified in NCERT Exemplar

(a, e) It is given that P, Q, R are having different dimensions. Hence cannot be added or subtracted, so we can say that (a) and (e) are not meaningful. We cannot say about the dimensions of product of these quantities. Hence b, c and d may be meaningful.