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Yes, the MBBS programme is offered at KSMU Russia, which is a 4-year program with the first-year fee of INR 4 L. International students are required to submit the documents mentioned below for the Kazan State Medical University admission process:

• Notarized Certificate of Secondary Education
• Notarized Certificate copy attested by the Ministry of Human Resource Development
• Notary attested copy of birth certificate
• Medical certificate with all important lab test results, including AIDS test
• Copy of national passport with a minimum validity of 9 months
• 12 recent passport-sized photographs on matt paper only

This is a short answer type question as classified in NCERT Exemplar

One atomic mass unit is 1/12 of the mass of carbon atom

Mass of one carbon atom = 12g

Number of atoms in one mole= Avogadro’s number

= 6.023 $\times$ 10²³

Mass of one ₆C¹² atom = $\frac{12}{6.023\times {10}^{23}}g$

1 amu= 1/12 of mass of carbon atom

1 amu= ( $\frac{1}{12}\times \frac{12}{6.023\times {10}^{23}}$ )g= 1.67 $\times {10}^{-27}kg$

This is a short answer type question as classified in NCERT Exemplar

A mass spectrograph is used for measuring the mass of atoms and molecules.

As per some unofficial sites, the Kazan State Medical University acceptance rate stands at 68% which makes it a moderately difficult university to get in, but with careful consideration of the admission requirements, the students can bag their offer letter.

This is a short answer type question as classified in NCERT Exemplar

Radius of atom = 1A^o=10^-10m

Radius of nucleus = 10^-15m

Volume of atom=V_A= 4/3 $\pi$ r³_a

Volume of nucleus V_N=4/3 $\pi$ r³_N

To finding the ratio

$\frac{V_A}{V_N}=\frac{\frac{4}{3}\pi r_a^3}{\frac{4}{3}\pi r_N^3}=\frac{r_a}{r_n}={10}^{15}$

This is a short answer type question as classified in NCERT Exemplar

The value of any given physical quantity may very over a wide range. Therefore different units of same physical quantity are required. As we know that to measuring distance of an object we need cm m, km, light year etc.

International students are required to apply to KSMU Russia via the official admission portal with copies of all scanned academic documents. Below are the steps to complete as online application process for this university: 

• Step 1: Fill up the MBBS admission form and submit the required documents on the Kazan State Medical University official portal
• Step 2: Wait for the offer letter to arrive
• Step 3: Submit the application form for a student visa along with original passport & other supporting documents
• Step 4: Pay the tuition fee or apply for an education loan if required

This is a long answer type question as classified in NCERT Exemplar

(a) 1 amu = 1.67 $\times$ 10^-27kg

And energy E=mc²= (1.67 $\times$ 10^-27) (3 $\times {10}^8$ )²J

E= 939.4MeV

(b) So dimensionally correct relation will be E=amu $\times$ c²

= 1uc²

= 931.5MeV

This is a long answer type question as classified in NCERT Exemplar

(a) 1 parsec =distance at which 1AU long arc subtends an angle of 1sec

1parsec = ( $\frac{1AU}{1arcsec}$ )

1 deg = 3600 arc sec

1 parsec = $\frac{\pi }{3600\times 180}rad$

1parsec = $\frac{3600\times 180}{\pi }AU$ = 2 $\times {10}^{5}AU$

(b) sun’s diameter is 1/2⁰

so at 1 parsec star is $\frac{1/2}{2\times {10}^5}$  degree in diameter= 15 $\times$ 10^-5 arc/min with magnification it looks like 15 $\times$ 10^-3

(c) $\frac{D_{mars}}{D_{earth}}=\frac{1}{2}$

we know that $\frac{D_{earth}}{D_{sun}}=\frac{1}{100}$

$\frac{D_{mars}}{D_{sun}}=\frac{1}{2}\times \frac{1}{100}$

At 1AU sun’s diameter =1/2⁰

Mars diameter = $\frac{1}{2}\times \frac{1}{200}=\frac{1}{400}$

AT 1/2AU

 Mars diameter will 1/200⁰ but with hundred magnification it is 1/2⁰

This is a long answer type question as classified in NCERT Exemplar

According to kepler’s law T² $\propto$  r³

T $\propto r^{3/2}$

T $\propto r^{\frac{3}{2}}{R}^a{g}^b$

T $\propto k{r}^{\frac{3}{2}}{R}^a{g}^b$

[M⁰L⁰T]=K [L]^3/2 [L]^a [LT^-2]^b

 = k [L^a+b+3/2T^-2b]

On comparing the powers of same terms we get

So a+b+3/2=0

So b=-1/2 and a=-1

T=kr^3/2R^-1g^-1/2

T= $\frac{k}{R}\sqrt[]{\frac{r^3}{g}}$

There is no application fee at KSMU Russia, although this university charges INR 20,000 for the overall registration process, which also includes the academic fees, visa, and registration fee, with other expenses. 

Other than the mentioned KSMU registration fee, the first-year tuition for the MBBS programme stands at INR 4L. It is to be noted that this fee does not include living expenses. 

International students can make a KSMU application via the official portal of this university with all the necessary documents such as: 

• Notarized Certificate of Secondary Education
• Notarized Certificate copy attested by the Ministry of Human Resource Development
• Notary attested copy of birth certificate
• Medical certificate with all important lab test results including AIDS test
• Copy of national passport with minimum validity of 9 months
• 12 recent passport-sized photographs in matt paper only

In general, there are two intakes available for KSMU admissions per academic year; the Autumn semester and the Spring semester. The autumn semester in 2025 will start in Sep 2025 and will end in Jan 2026. On the other hand, the Spring semester will start in Feb and will end in Jun 2025. The tentative admission deadlines for Kazan State Medical University are given below.

Students must have passed Class 12 from a recognised by State or Central Education Board. They must have taken five subjects in Class 12 with an aggregate score of 50%. The university has not specified the subjects required in Class 12/ equivalent examination. So Maths is not compulsory to take admission to the BCom (Hons) course of SRM University.