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${\displaystyle \underset{0}{\overset{\pi }{\int }}\frac{x^{2}sinx\cdot cosx}{si{n}^{4}x+co{s}^{4}x}dx}$

$={\displaystyle \underset{0}{\overset{\frac{\pi }{2}}{\int }}\frac{sinxcosx}{si{n}^{4}x+co{s}^{4}x}\left(x^2-{\left(\pi -x\right)}^2\right)dx}$

$={\displaystyle \underset{0}{\overset{\frac{\pi }{2}}{\int }}\frac{sinx\cdot cosx\left(2\pi x-{\pi }^2\right)}{si{n}^{4}x+co{s}^{4}x}x}$

$=2\pi \cdot \frac{\pi }{4}{\displaystyle \underset{0}{\overset{\frac{\pi }{2}}{\int }}\frac{sinxcosx}{si{n}^{4}x+co{s}^{4}x}dx}-{\pi }^2{\displaystyle \underset{0}{\overset{\frac{\pi }{2}}{\int }}\frac{sinxcosx}{si{n}^{4}x+co{s}^{4}x}dx}$

$=-\frac{{\pi }^2}{2}{\displaystyle \underset{0}{\overset{\frac{\pi }{2}}{\int }}\frac{sinxcosx}{si{n}^{4}x+co{s}^{4}x}dx}$

$=-\frac{{\pi }^2}{2}{\displaystyle \underset{0}{\overset{\frac{\pi }{2}}{\int }}\frac{\frac{1}{2}sin2x}{1-\frac{1}{2}si{n}^{2}2x}dx}$

$=-\frac{{\pi }^2}{2}{\displaystyle \underset{0}{\overset{\frac{\pi }{2}}{\int }}\frac{sin2x}{2-si{n}^{2}2x}dx}$

$=-\frac{{\pi }^2}{2}{\displaystyle \underset{0}{\overset{\frac{\pi }{2}}{\int }}\frac{sin2x}{1+co{s}^{2}2x}dx}$

Let cot2x = t

$=-\frac{{\pi }^2}{2}{\displaystyle \underset{1}{\overset{-1}{\int }}\frac{-\frac{1}{2}dt}{1+t^2}}$

$=-\frac{{\pi }^2}{4}{\displaystyle \underset{-1}{\overset{1}{\int }}\frac{dt}{1+t^2}}$

$=-\frac{{\pi }^2}{4}\cdot \frac{\pi }{2}=-\frac{{\pi }^2}{8}$

$\frac{120}{{\pi }^3}\left|-\frac{{\pi }^3}{8}\right|=15$

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Take $\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}=\lambda$  

x = 2λ + 1, y = 3λ + 2, z = 4λ + 3

  $\overrightarrow{AB}$  = (α − 2)  $\widehat{i}$ + (β − 3) $\widehat{j}$ + (γ − 4) $\widehat{k}$  

Now,

(α − 2) ⋅ 2 + (β − 3) ⋅3 + (γ − 4) ⋅ 4 = 0

2α − 4 + 3β − 9 + 4γ −16 = 0

⇒ 2α + 3β + 4γ = 29

Some courses that provide high scope include BDes, BSc in Physics, BBA, MBBS, CAT, and BCA.

Which course is better after 10th completely depends on the personal career goals and preferences of students. Many students choose Science stream for better future opportunities. However, the trend of Diploma and vocational courses is also rising nowadays. 

  $f\left(x\right)=e^{x^3-3x+1}$

$f\text{'}\left(x\right)=e^{x^3-3x+1}$  (3x² − 3)

$e^{x^3-3x+1}$ = ⋅ 3(x −1)(x +1)

For x ∈ (−∞, −1], f '(x) ≥ 0

∴     f(x) is increasing function

∴     a = e^–∞ = 0 = f (−∞)

b = e⁻¹⁺³⁺¹ = e³ = f (−1)

∴     P(4, e³ + 2)

$d=\frac{\left(e^3+2\right)\left(e^{-3}\right)}{\sqrt[]{1+e^{-6}}}=\frac{1+2e^{-3}}{\sqrt[]{1+e^{-6}}}=\frac{1+2e^{-3}}{\sqrt[]{1+e^{-6}}}=\frac{e^3+2}{\sqrt[]{e^6+1}}$

Yes, you can fill out the CLAT Application Form in phases. There is an option to save in every step. However, it will be better if you fill the form in one go. For this, you should keep all the documents ready in hand. See if you fill the form in one go you don't have to worry about it. 

The questions asked in Logical reasoning are from Alphanumeric Series, Reasoning Analogies, Blood Relations, Coding Decoding, Odd One Out. Picture Series and Sequences, Pattern Series and Sequences, Seating Arrangements, Statement and Assumptions, Syllogism. Apply various 10h ständard mathematical operations on such information, including from areas such as ratios and proportions, basic algebra, Profit and Loss, Time & Work, Average, Speed and distance, Ratio and Proportion. 

$=8*7*6*5*4+\frac{9*8}{2}$

= 6756

The questions in the english section of RULET exam are asked from the topics such as, Tenses, Phrasal Verbs and idioms, Co-ordination and subordination, Articles and Determiners, Active & Passive Voice, Direct and Indirect Speech, Antonyms and Synonyms, Modals expressing various concepts (Obligation, Request, Permission, Prohibition, Intention, Condition, Probability, Possibility, Purpose, Reason, Companions, Contrast).

As per the UniRaj official website, RULET exam consists of 4 sections:

1. English Language,
2. Legal Reasoning,
3. Current Affairs & GK
4. Logical Aptitude & Quantitative Aptitude 

The detailed syllabus of RULET 2026 as provided by the University of Rajasthan through the official notification. Candidates looking to sit for the exam must practice the questions related to these sections to ace the exam in first attempt. 

(y – 2) = m (x – 8)

⇒   x-intercept

⇒     $\left(\frac{-2}{m}+8\right)$

⇒   y-intercept

⇒   (–8m + 2)

⇒   OA + OB = $\frac{-2}{m^2}$  + 8 – 8m + 2

$f\text{'}\left(m\right)=\frac{2}{m^2}-8=0$  

-> $m^2=\frac{1}{4}$

-> $m=\frac{-1}{2}$

-> $f\left(\frac{-1}{2}\right)=18$

->Minimum = 18

Take e^sinx = t (t > 0)

⇒ $t-\frac{2}{t}=2$

⇒   $\frac{t^2-2}{t}=2$

->t² – 2t – 2 = 0

->t² – 2t + 1 = 3

⇒   (t −1)² = 3

⇒   t = 1 ± $\sqrt[]{3}$  

⇒   t = 1 ± 1.73

⇒   t = 2.73 or –0.73 (rejected as t > 0)

⇒   e^{sin x} = 2.73

->log_e e^{sin x} = log_e 2.73

⇒ sin x = log_e 2.73 > 1

So no solution.

RULET entrance exam is conducted once in a year by the University of Rajasthan. This exam is conducted for admission to the undergraduate Law courses. Aspiring candidates will have to keep checking the official notification for the registration of the entrance exam. The exam is tentatively held in the month of May or June every year.

Candidates who do not belong to the Rajasthan state can also apply for the RULET exam if they wish to pursue the course from University of Rajasthan. The interested candidates will have to apply for the entrance exam within the deadline as per the official notification. The registered candidates will then be issued the admit card which will be required during the examination for verification. 

Candidates can check the list of documents required to fill the registration form for CLAT below:

• Passport-Size Photograph 
• Scanned Signature 
• Class 10 Marksheet/Certificate 
• Class 12 Marksheet
• Category Certificate
• PwD Certificate
• Domicile Certificate
• Valid Photo ID Proof
• Email ID and Mobile Number