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Joining the top Dental colleges accepting NEET scores in India can be expensive as most colleges have tuition fees of more than INR 5 lakh. However, listed below are some affordable colleges along with their tuition fees:

Disclaimer: This information is sourced from official website/ media reports/ NIRF website and may vary.

$\left|z-3\sqrt[]{2}\right|+\left|z-p\sqrt[]{2}i\right|$ is minimum for z,  $3\sqrt[]{2}\&p\sqrt[]{2}i$ are collinear.

$\iff {\left(3\sqrt[]{2}\right)}^2+{\left(p\sqrt[]{2}\right)}^2={\left(5\sqrt[]{2}\right)}^2$

$\Rightarrow 18+2p^2=50$

$2p^2=32$

$p=\pm 4$

The seat intake for BBA course at Directorate of Distance and Continuing Education, Utkal University is 100. However, this may change if the university requires. Candidates must apply prior to the last date since admissions to this course is on first come and first serve basis. This will also give the university time to evaluate the candidate's form. 

. Universities Accepting Students Without CUET (Direct / Merit-based)

Many private universities, state universities (in some states), and deemed universities still allow admission without CUET. Examples:

University / College Location Mode of Admission

Ashoka University Sonipat, Haryana Own entrance & interview

OP Jindal Global University Sonipat, Haryana Merit + SOP/interview

Amity University Noida + other campuses Merit-based + interview

Christ University Bengaluru + NCR campuses Own entrance (CUET optional)

Flame University Pune Aptitude test + interview

MIT-World Peace University Pune M

erit-based

$\frac{K_2}{k_1}=9\frac{A_1}{A_2}=2,\frac{L_1}{L_2}=2$

$\frac{450-T}{\frac{L_1}{A_1{k}_1}}=\frac{T}{\frac{L_2}{k_2{A}_2}}\Rightarrow \left(450-T\right)\frac{L_2}{K_2{A}_2}=\left(T\right)\frac{L_1}{A_1{k}_1}$

$\left(450-T\right)=T\left(\frac{L_1}{L_2}\frac{k_2{A}_2}{k_1{A}_1}\right)$ $\Rightarrow 450-T=T\left(2\times 9\times \frac{1}{2}\right)=9T$

10 T = 450

T = 45° C

Yes, joining the top Dental colleges in India accepting NEET scores can be worthwhile for you. For that, you need to check its ROI. Listed below are some colleges along with their tuition fees and average placement package:

Disclaimer: This information is sourced from official website/ media reports/ NIRF website and may vary.

The fees of studying BCom course at Directorate of Distance and Continuing Education, Utkal University is INR 26,900. This is the total tuition fee and the overall fee may include other components like exam fee, application fee, security deposits, etc. Candidates must pay this fee to confirm their seat after getting selected for admission. For more details on fees, candidates can check the official website. 

Listed below are the top ranked Dental colleges in India accepting NEET scores along with their NIRF ranking over the past three years:

Disclaimer: This information is sourced from official website of the ranking body listed and may vary.

According to definition of wave number, we can write

$\frac{1}{\lambda }=R\left(\frac{1}{1^2}-\frac{1}{n^2}\right)\Rightarrow 1-\frac{1}{n^2}=\frac{1}{\lambda R}$$$

$\Rightarrow \frac{1}{n^2}=1-\frac{1}{\lambda R}=\frac{\lambda R-1}{\lambda R}\Rightarrow n=\sqrt[]{\frac{\lambda R}{\lambda R-1}}$

$\frac{E_A}{E_B}=\frac{-\frac{GM{m}_A}{2\times 3r}}{\frac{-GM{m}_B}{2\times 4r}}=\frac{m_A}{m_B}\times \frac{4}{3}=\frac{4}{3}\times \frac{4}{3}=\frac{16}{9}$

To excel in both innovation management and entrepreneurship, students must seek a curriculum which is in sync with their prospects and that seamlessly integrates theoretical knowledge with empirical application,   fostering a mindset and the skill set required to thrive in the industry.

$H=l^{2}Rt$

$\mathrm{\%}errorinH=\frac{\Delta H}{H}\times 100=2\left(\frac{\Delta l}{l}\right)\times 100+\left(\frac{\Delta R}{R}\right)\times 100+\left(\frac{\Delta t}{t}\right)\times 100=2\times 2+1+3=8\mathrm{\%}$

$H=\frac{u^{2}si{n}^2\theta }{2g}andR=\frac{u^{2}sin2\theta }{g}$

According to question

$R=H\Rightarrow \frac{u^{2}si{n}^2\theta }{2g}=\frac{2u^{2}sn\theta cos\theta }{g}\Rightarrow tan\theta =4$

Indeed, adding industry trends or insights to your SOP will make your application more thorough and pertinent. Talking about the new developments in the field of MIS, cutting-edge technologies, or creative approaches, shows that you understand the dynamics of the business and can adjust to changing trends. You can demonstrate that you are prepared to make a significant contribution to the programme and succeed in your future MIS job by demonstrating your grasp of the industry landscape.

As per NIRF ranking 2025, Maulana Azad Institute of Dental Sciences, MAMC emerged to be as the top Dental college accepting NEET in India followed by Manipal College of Dental Sciences Manipal and A.B. Shetty Memorial Institute of Dental Sciences.

Of course! Your SOP is a great way to demonstrate your technical know-how and command of the programming languages or other pertinent software tools used in MIS. Showcasing your abilities and expertise in data analytics, database administration, or software development can bolster your application and indicate that you are prepared for the program.

$v=\frac{m{v}_0}{M+m}\Rightarrow K_f=\frac{1}{2}\left(M+m\right)v^2=\frac{m{v}_0^2}{2\left(M+m\right)}$

$K_i=\frac{m{v}_0^2}{2}$

Loss in Kinetic energy = $\Delta K=K_i-K_f$

$\Delta K=\frac{1}{2}m{v}_0^2\left(\frac{M}{M+m}\right)=\frac{1}{2}\times 0.2\times 100=\left[\frac{9.8}{10}\right]=9.8J$