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New Question

5 months ago

0 Follower 8 Views

P
Porishmita Paul

Contributor-Level 10

Yes, there are several job options after 10th pass for girls such as Data Entry Operator, Call Center Executive, Beauty Therapist, and Retail/Sales jobs. Many of these roles offers quick earning opportunities.

New Question

5 months ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

f' (c) = 1 + lnc = e/ (e-1)
lnc = e/ (e-1) - 1 = (e - (e-1)/ (e-1) = 1/ (e-1)
c = e^ (1/ (e-1)

New Question

5 months ago

0 Follower 1 View

A
Anshul Jindal

Contributor-Level 10

The DEd (Diploma in Elementary Education) course offers a wide scope in elementary education, primarily qualifying you for roles like primary school teacher and special education teacher in government and private schools. It also opens avenues as a home tutor, content developer for educational websites, curriculum developer, education counsellor, or in roles within pre-school and daycare centers. The DEd course provides the skills and knowledge to teach at the elementary level, with some specialisation in inclusive education, and can serve as a foundation for further education like a BEd.

New Question

5 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

log (k? /k? ) = (Ea / 2.303R) [1/T? - 1/T? ]
log (3.555) = (Ea / (2.303R) [1/303 - 1/313]
1.268 × 8.314 × 303 × 313 = 10Ea
So, Ea = 100 kJ

New Question

5 months ago

0 Follower 9 Views

R
Raj Pandey

Contributor-Level 9

Equation of line is x/3 + y/1 = 1
⇒ x + 3y - 3 = 0
The image (x? , y? ) of point (-1, -4) is given by:
(x? - (-1)/1 = (y? - (-4)/3 = -2 (1 (-1) + 3 (-4) - 3) / (1² + 3²)
(x? + 1)/1 = (y? + 4)/3 = -2 (-1 - 12 - 3)/10 = -2 (-16)/10 = 16/5
x? + 1 = 16/5 ⇒ x? = 11/5
(y? + 4)/3 = 16/5 ⇒ y? + 4 = 48/5 ⇒ y? = 28/5

New Question

5 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

According to IUPAC convention for naming of elements with atomic number more than 100, different digits are written in order and at the end ium is added. For digits following naming is used.

0 -nil

1-un

2-bi

3-tri

and so on.

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5 months ago

0 Follower 3 Views

S
Sayeba Naushad

Contributor-Level 10

There are a total of 19 NIFTs in India that participate in the NIFT admission process. The participating institutes offer B.Des, M.Des, B.F.Tech, M.F.Tech, and M.F.M courses. Admission to the participating institutes will be on the basis of NIFT scores. NIFT Varanasi is the newly added college to the list of NIFT participating colleges. 

New Question

5 months ago

0 Follower 10 Views

A
Aashi Madavi

Contributor-Level 8

Amity University Kolkata offers admission based on merit and entrance. Admission to courses such as MBA would require a valid CAT score. Apart from CAT, candidates can appear for other accepted entrance exams as well such as XAT/ MAT/ NMAT/ CMAT and others. Candidates must meet the cutoff by securing the rank or score marked by the University during admissions.

New Question

5 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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5 months ago

0 Follower 6 Views

M
Meitankeisangbam Vasundhara devi

Contributor-Level 10

The IMDR Pune has been has had a strong record when it comes to placements. Check out the IMDR Pune placements between 2022-2024 presented below:

Particulars

Placement Statistics (2022)

Placement Statistics (2023)

Placement Statistics (2024)

the highest Package

INR 10 LPA

INR 12.90 LPA

INR 14.71 LPA

Average Package

INR 5.43 LPA

INR 6.75 LPA

INR 6.56 LPA

the lowest Package 

INR 3.6 LPA

INR 3.6 LPA

NA 

Total Students Placed

107

138

142

Total students registered

117

146

180

Placement Rate

96%

90%

92%

New Question

5 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution 

 

New Question

5 months ago

0 Follower 2 Views

N
Neha Arora

Contributor-Level 10

With a rank of 2000 in CCMN, it is possible to get admission to NIT Arunachal Pradesh. The last round closing rank for admission to the college among the General AI category candidates was 1972. Thus with rank, there is high chance of getting admission to the course. 

New Question

5 months ago

0 Follower 7 Views

R
Raj Pandey

Contributor-Level 9

y = (2/π x - 1)cosec x
dy/dx = (2/π)cosec x - (2/π x - 1)cosec x cot x
⇒ dy/dx + (2/π x - 1)cosec x cot x = 2/π cosec x
⇒ dy/dx + ycot x = 2/π cosec x
This is a linear differential equation. The integrating factor P (x) is the coefficient of y.
⇒ P (x) = cot x

New Question

5 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Applying Rolle's theorem in for function f (x), there exists c such that f' (c) = 0, c ∈ (0,1).
Again applying Rolle's theorem in [0, c] for function f' (x), there exists c? such that f' (c? ) = 0, c? ∈ (0, c).
Option A is correct.

New Question

5 months ago

0 Follower 2 Views

A
Ashwin Yadav

Contributor-Level 10

Adamas University offers a large diversity of courses to students in Management field. Adamas University admissions are held on the basis of entrance tests. Students seeking course admissions must clear their previous qualifying examination and appear for any of the prescribed entrance exams such as XAT, CAT, MAT, Adamas AUAT, among others. Students can visit the official website to learn more regarding the course-wise eligibility and specialisation details.

New Question

5 months ago

0 Follower 1 View

N
Nishtha Sharma

Contributor-Level 10

Yes, Tohoku University offers a large variety of scholarships for its international students. Tohoku University offers various scholarships for international students which are available after applicants have arrived in Japan and are provided through local governments, associations or foundations. A few Tohoku University scholarships for Indian student are listed below:

Scholarship

Details

MEXT (University & Embassy Recommendation)

Full support (stipend, fees, airfare) via official routes

Monbukagakusho Honors Scholarship (JASSO)

JPY 48,000 (INR 28,806)/month stipend for privately funded students

Sakata Agri Foundation Scholarship

JPY 100,000 (INR 60,020)/month for agriculture students from India (JLPT N3 required)

JEES T. Banaji Indian Student Scholarship

Indian nationals; Japanese proficiency not strictly required

Other Private Foundation Scholarships (Engineering etc.)

Varies by foundation; some accept internationals including Indian students

MEXT through SIM in ICEEC programme (Dept-specific)

Eligible for MEXT with stipend & fees waived

Source: Tohoku University Official Website

Conversion used: JPY 1 - INR 0.60

New Question

5 months ago

0 Follower 2 Views

J
Jaya Sharma

Contributor-Level 10

Refractive index (n) is a dimensionless quantity that has no units. Since both numerator and denominator are in meters per seconds (m/s), both units cancel each other. This makes refractive index simply a number. 

New Question

5 months ago

0 Follower 4 Views

A
Ashwin Yadav

Contributor-Level 10

LEAD College of Management provides various programmes and specialisations to students. For obtaining LEAD College of Management admission, candidates are required to appear for the prescribed entrance tests. Students can visit the official website of the LEAD College of Management to learn more regarding the eligibility details for their preferred course choice. Accepted exams include CMAT, KMAT Kerala, and CAT.

New Question

5 months ago

0 Follower 9 Views

R
Raj Pandey

Contributor-Level 9

Given equation is 2x (2x + 1) = 1 ⇒ 4x² + 2x - 1 = 0. Roots of the equation are α and β.
∴ α + β = -2/4 = -1/2 ⇒ β = -1/2 - α
and
4α² + 2α - 1 = 0 ⇒ α² = (1-2α)/4 = 1/4 - α/2
Now
α = 1/2 - 2α²
Substituting into the expression for β:
β = -1/2 - (1/2 - 2α²) = -1 + 2α²

New Question

5 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

(x/m) = k (P)¹/?
log (x/m) = log k + (1/n) log P
Slope = 1/n = 2 So n = ½
Intercept ⇒ log k = 0.477 So k = Antilog (0.477) = 3
So (x/m) = k (P)¹/? = 3 [0.04]² = 48 × 10?

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