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This is a Assertion Type Questions as classified in NCERT Exemplar

60. Option (i)

i.e.,   Both A and R are correct, and R is the correct explanation of A is the answer. Since the liquids are having sufficient difference in their boiling points. Liquids having different boiling points vaporize at different temperatures. The vapours are cooled, and the liquids so formed are collected separately. 

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This is a short answer type question as classified in NCERT Exemplar

The element from group 2 is beryllium. Be (OH)₂ is amphoteric. It reacts with both acids and bases. It reacts with acid to form beryllium chloride and it reacts with base to form beryllate ion which is soluble in sodium hydroxide. The reaction is shown below.

Be (OH)₂+2OH−→ [Be (OH)₄]²⁻

Be (OH)₂+2HCl→BeCl₂+2H₂O

Beryllium sulfate are readily soluble in water.

The TAPMI accepts several exam scores including CAT, CMAT, XAT, and NMAT. It has released separate cutoffs for separate exam for different MBA specilisations. Considering the TAPMI MBA cutoff 2024, the percentile needed to get into TAPMI for Master of Business Administration (MBA) is 95, 85, 80 (score), and 80 for CMAT, CAT, NMAT, and XAT, respectively. For more specialisations' cutoffs, candidates can check out the official page:

This is a Matching Type Questions as classified in NCERT Exemplar

59.  (i) → (a); (ii) → (b); (iii) → (b) : (iv) → (c)

There are more than 40 MMS colleges in Mumbai. Of these, 30 colleges are privately owned, 1 is owned by public-private organizations, and 3 colleges are owned by the government. Admission to these colleges is based on entrance exams like MAH CET, CMAT, CAT, ATMA, MAT, XAT, etc.

This is a short answer type question as classified in NCERT Exemplar

These two elements have similar properties because of their similar atomic and ionic radii.

(i) Both are lighter element and harder than the other metals in their respective groups.

(ii) The halides of both elements, LiCl and MgCl₂ are soluble in ethanol.

The cost of the TOEFL iBT exam in India is INR 17,999.72. This includes the fees of TOEFL registration and reporting of scores to up to four institutions or agencies. 

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Deadline to submit the JEST 2026 application form will be first week of June 2026. It is advised to check website on regular basis so that students can never miss update regarding dates and important events.

This is a Matching Type Questions as classified in NCERT Exemplar

58. (i) →   (a); (ii) →   (a); (iii) →   (b)

S.P. Mandali's Ramnarain Ruia Autonomous College first merit list 2025 has been released for admission to multiple UG courses. For the General category students, the first round cutoff percentages fell between 44.67 and 94.6. Among all the courses, the one with the highest cutoff percentage was BSc in Biotechnology. The highest cutoff indicates the competiton level among the aspirants for admission to the course. For detailed cutoff information for other courses and specialsiations, check out the table below: 

(i) Given, A = $\left[\begin{array}{ccc}\hfill -1\hfill & \hfill 2\hfill & \hfill 3\hfill \\ \hfill 5\hfill & \hfill 7\hfill & \hfill 9\hfill \\ \hfill -2\hfill & \hfill 1\hfill & \hfill 1\hfill \end{array}\right]$ and B = $\left[\begin{array}{ccc}\hfill -4\hfill & \hfill 1\hfill & \hfill 1\hfill \\ \hfill 1\hfill & \hfill 2\hfill & \hfill 3\hfill \\ \hfill -5\hfill & \hfill 0\hfill & \hfill 1\hfill \end{array}\right]$

Then, A’ = $\left[\begin{array}{ccc}\hfill -1\hfill & \hfill 5\hfill & \hfill -2\hfill \\ \hfill 2\hfill & \hfill 7\hfill & \hfill 1\hfill \\ \hfill 3\hfill & \hfill 9\hfill & \hfill 1\hfill \end{array}\right]$ and B = $\left[\begin{array}{ccc}\hfill -4\hfill & \hfill 1\hfill & \hfill 1\hfill \\ \hfill 1\hfill & \hfill 2\hfill & \hfill 3\hfill \\ \hfill -5\hfill & \hfill 0\hfill & \hfill 1\hfill \end{array}\right]$

A + B = $\left[\begin{array}{ccc}\hfill -1\hfill & \hfill 2\hfill & \hfill 3\hfill \\ \hfill 5\hfill & \hfill 7\hfill & \hfill 9\hfill \\ \hfill -2\hfill & \hfill 1\hfill & \hfill 1\hfill \end{array}\right]$ + $\left[\begin{array}{ccc}\hfill -4\hfill & \hfill 1\hfill & \hfill -5\hfill \\ \hfill 1\hfill & \hfill 2\hfill & \hfill 0\hfill \\ \hfill 1\hfill & \hfill 3\hfill & \hfill 1\hfill \end{array}\right]$ = $\left[\begin{array}{ccc}\hfill -1-4\hfill & \hfill 2+1\hfill & \hfill 3-5\hfill \\ \hfill 5+1\hfill & \hfill 7+2\hfill & \hfill 9+0\hfill \\ \hfill -2+1\hfill & \hfill 1+3\hfill & \hfill 1+1\hfill \end{array}\right]$ = $\left[\begin{array}{ccc}\hfill -5\hfill & \hfill 3\hfill & \hfill -2\hfill \\ \hfill 6\hfill & \hfill 9\hfill & \hfill 9\hfill \\ \hfill -1\hfill & \hfill 4\hfill & \hfill 2\hfill \end{array}\right]$

LHS. = (A + B)’ = $\left[\begin{array}{ccc}\hfill -5\hfill & \hfill 6\hfill & \hfill -1\hfill \\ \hfill 3\hfill & \hfill 9\hfill & \hfill 4\hfill \\ \hfill -2\hfill & \hfill 9\hfill & \hfill 2\hfill \end{array}\right]$

RHS = A’+ B’ = $\left[\begin{array}{ccc}\hfill -1\hfill & \hfill 5\hfill & \hfill -2\hfill \\ \hfill 1\hfill & \hfill 7\hfill & \hfill 1\hfill \\ \hfill 3\hfill & \hfill 9\hfill & \hfill 1\hfill \end{array}\right]+\left[\begin{array}{ccc}\hfill -4\hfill & \hfill 1\hfill & \hfill 1\hfill \\ \hfill 1\hfill & \hfill 2\hfill & \hfill 3\hfill \\ \hfill -5\hfill & \hfill 0\hfill & \hfill 1\hfill \end{array}\right]=\left[\begin{array}{ccc}\hfill -1-4\hfill & \hfill 5+1\hfill & \hfill -2+1\hfill \\ \hfill 2+1\hfill & \hfill 7+2\hfill & \hfill 1+3\hfill \\ \hfill 3-5\hfill & \hfill 9+0\hfill & \hfill 1+1\hfill \end{array}\right]$ = $\left[\begin{array}{ccc}\hfill -5\hfill & \hfill 6\hfill & \hfill -1\hfill \\ \hfill 3\hfill & \hfill 9\hfill & \hfill 4\hfill \\ \hfill -2\hfill & \hfill 9\hfill & \hfill 2\hfill \end{array}\right]$ = L H S

$\therefore$ (A + B)’ = A’+ B’

(ii) A – B = $\left[\begin{array}{ccc}\hfill -1\hfill & \hfill 2\hfill & \hfill 3\hfill \\ \hfill 5\hfill & \hfill 7\hfill & \hfill 9\hfill \\ \hfill -2\hfill & \hfill 1\hfill & \hfill 1\hfill \end{array}\right]-\left[\begin{array}{ccc}\hfill -4\hfill & \hfill 1\hfill & \hfill -5\hfill \\ \hfill 1\hfill & \hfill 2\hfill & \hfill 0\hfill \\ \hfill 1\hfill & \hfill 3\hfill & \hfill 1\hfill \end{array}\right]=\left[\begin{array}{ccc}\hfill -1-\left(-4\right)\hfill & \hfill 2-1\hfill & \hfill 3-(5)\hfill \\ \hfill 5-1\hfill & \hfill 7-2\hfill & \hfill 9-0\hfill \\ \hfill -2-1\hfill & \hfill 1-3\hfill & \hfill 1-1\hfill \end{array}\right]=\left[\begin{array}{ccc}\hfill 3\hfill & \hfill 1\hfill & \hfill 8\hfill \\ \hfill 4\hfill & \hfill 5\hfill & \hfill 9\hfill \\ \hfill -3\hfill & \hfill -2\hfill & \hfill 0\hfill \end{array}\right]$

L.H.S. = (A − B)’ = $\left[\begin{array}{ccc}\hfill 3\hfill & \hfill 4\hfill & \hfill -3\hfill \\ \hfill 1\hfill & \hfill 5\hfill & \hfill -2\hfill \\ \hfill 8\hfill & \hfill 9\hfill & \hfill 0\hfill \end{array}\right]$

R.H.S. = A’ − B’ = $\left[\begin{array}{ccc}\hfill -1\hfill & \hfill 5\hfill & \hfill -2\hfill \\ \hfill 2\hfill & \hfill 7\hfill & \hfill 1\hfill \\ \hfill 3\hfill & \hfill 9\hfill & \hfill 1\hfill \end{array}\right]- \left[\begin{array}{ccc}\hfill -4\hfill & \hfill 1\hfill & \hfill 1\hfill \\ \hfill 1\hfill & \hfill 2\hfill & \hfill 3\hfill \\ \hfill -5\hfill & \hfill 0\hfill & \hfill 1\hfill \end{array}\right]=$ $\left[\begin{array}{ccc}\hfill -1-(-4)\hfill & \hfill 5-1\hfill & \hfill -2-1\hfill \\ \hfill 2-1\hfill & \hfill 7-2\hfill & \hfill 1-3\hfill \\ \hfill 3-(-5)\hfill & \hfill 9-0\hfill & \hfill 1-1\hfill \end{array}\right]=\left[\begin{array}{ccc}\hfill 3\hfill & \hfill 4\hfill & \hfill -3\hfill \\ \hfill 1\hfill & \hfill 5\hfill & \hfill -2\hfill \\ \hfill 8\hfill & \hfill 9\hfill & \hfill 0\hfill \end{array}\right]$

$\therefore$ (A − B)’ = A’ − B’

This is a short answer type question as classified in NCERT Exemplar

(i) O₂²⁻+ 2H₂O → H₂O₂+2OH⁻

(ii) 2O₂⁻+2H₂O→2OH⁻+H₂O₂+O₂

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