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No, the students who don't make it to the IIM shortlist of a particular year, they will not be considered for admission. Such candidates can appear for CAT again the next year and try for admission. If a candidate doesn't make it to the first shortlist, they can wait for the second shortlist to release in which they might be selected.

This is a Multiple Choice Questions as classified in NCERT Exemplar

55. Options (i) and (ii) are correct since hyperconjugation involves the delocalization of electrons of C—H bond of an alkyl group directly attached to an atom of unsaturated system or to an atom with an unshared p-orbital. The electrons of C—H bond of the alkyl group enter into partial conjugation with the attached unsaturated system or with the unshared p-orbital. This is a permanent effect. Hyperconjugation can be shown as-

Yes, pursuing an BTech course from Ahmedabad University is a good choice if considering the placement opportunities. The placement packages are yet to be out. Meanwhile, check out the complete insights of Ahmedabad University placement for the overall Class of 2025 in the table below:

Given,A = $\left[\begin{array}{rr}\hfill 3& \hfill -2\\ \hfill 4& \hfill -2\end{array}\right]$

A² = A. A = $\left[\begin{array}{ll}3\hfill & -2\hfill \\ 4\hfill & -2\hfill \end{array}\right]\left[\begin{array}{ll}3\hfill & -2\hfill \\ 4\hfill & -2\hfill \end{array}\right]$

$=\left[\begin{array}{ll}3\times 3+(-2)\times 4\hfill & 3\times (-2)+(-2)\times (-2)\hfill \\ 4\times 3+(-2)\times 4\hfill & 4\times (-2)+(-2)\times (-2)\hfill \end{array}\right]$

$=\left[\begin{array}{ll}9-8\hfill & -6+4\hfill \\ 12-8\hfill & -8+4\hfill \end{array}\right]=\left[\begin{array}{ll}1\hfill & -2\hfill \\ 4\hfill & -4\hfill \end{array}\right].$

So,A²= xA2I.

$\Rightarrow \left[\begin{array}{cc}\hfill 1\hfill & \hfill -2\hfill \\ \hfill 4\hfill & \hfill -4\hfill \end{array}\right]=u\left[\begin{array}{cc}\hfill 3\hfill & \hfill -2\hfill \\ \hfill 4\hfill & \hfill -2\hfill \end{array}\right]-2\left[\begin{array}{ll}1\hfill & 0\hfill \\ 0\hfill & 1\hfill \end{array}\right].$

$\Rightarrow \left[\begin{array}{cc}\hfill 1\hfill & \hfill -2\hfill \\ \hfill 4\hfill & \hfill -4\hfill \end{array}\right]=\left[\begin{array}{cc}\hfill 3x\hfill & \hfill -2x\hfill \\ \hfill 4x\hfill & \hfill -2x\hfill \end{array}\right]-\left[\begin{array}{ll}2\hfill & 0\hfill \\ 0\hfill & 2\hfill \end{array}\right]=\left[\begin{array}{cc}\hfill 3x-2\hfill & \hfill -2x\hfill \\ \hfill 4x\hfill & \hfill -2x-2\hfill \end{array}\right].$

This is a long answer type question as classified in NCERT Exemplar

The element imparts yellow colour to the flame in flame test which means the element of group 1 is sodium. Sodium is used in the transmission of nerve signals and transport of sugars and amino acids into cells. Reactions are shown below.

2Na+O₂→Na₂O₂

4Na+O₂→2Na₂O

2Na₂O+O₂→2Na₂O₂

The candidates can check their admission status in IIM shortlist of each institute on their respective websites. The IIMs releases their shortlist on different days in the month of January. Once the shortlist is announced, candidates can check their status on the institute's website by using their CAT login ID. Such candidates can fill the PI form for participating in the WAT-PI round. If shortlisted, they are invited by the institute via email.

The median salary trend witnessed during PSIT College of Higher Education placements over the past three years is presented below:

Yes, PSIT College of Higher Education provides good placements to its students. The key highlights of PSIT College of Higher Education placements 2024 as compared with 2023 and 2022 are presented below:

Yes, as per the official website of JEST, the deadline to submit the JEST 2025 Application Form has been extended from May 30, 2025, to June 1, 2025, 11:55 pm. Candidates must visit the official website to submit their JEST application form before the end date. 

Given A = $\left[\begin{array}{ccc}\hfill 1\hfill & \hfill 0\hfill & \hfill 2\hfill \\ \hfill 0\hfill & \hfill 2\hfill & \hfill 1\hfill \\ \hfill 2\hfill & \hfill 0\hfill & \hfill 3\hfill \end{array}\right]$

A² = AA = $\left[\begin{array}{ccc}\hfill 1\hfill & \hfill 0\hfill & \hfill 2\hfill \\ \hfill 0\hfill & \hfill 2\hfill & \hfill 1\hfill \\ \hfill 2\hfill & \hfill 0\hfill & \hfill 3\hfill \end{array}\right]\left[\begin{array}{ccc}\hfill 1\hfill & \hfill 0\hfill & \hfill 2\hfill \\ \hfill 0\hfill & \hfill 2\hfill & \hfill 1\hfill \\ \hfill 2\hfill & \hfill 0\hfill & \hfill 3\hfill \end{array}\right]$

$=\left[\begin{array}{ccc}\hfill 1\times 1+0\times 0+2\times 2\hfill & \hfill 1\times 0+2\times 0+2\times 0\hfill & \hfill 1\times 2+0\times 1+2\times 3\hfill \\ \hfill 0\times 1+2\times 0+1\times 2\hfill & \hfill a\times 0+2\times 2+1\times 0\hfill & \hfill 0\times 2+2\times 1+1\times 3\hfill \\ \hfill 2\times 1+0\times 0+3\times 2\hfill & \hfill 2\times 0+0\times 2+3\times 0\hfill & \hfill 2\times 2+0\times 1+3\times 3\hfill \end{array}\right]$

$=\left[\begin{array}{l}1+402+6\\ 242+3\\ 2+604+9\end{array}\right]=\left[\begin{array}{ccc}\hfill 5\hfill & \hfill 0\hfill & \hfill 8\hfill \\ \hfill 2\hfill & \hfill 4\hfill & \hfill 5\hfill \\ \hfill 8\hfill & \hfill 0\hfill & \hfill 13\hfill \end{array}\right]$

A³ = A²A = $\left[\begin{array}{ccc}\hfill 5\hfill & \hfill 0\hfill & \hfill 8\hfill \\ \hfill 2\hfill & \hfill 4\hfill & \hfill 5\hfill \\ \hfill 8\hfill & \hfill 0\hfill & \hfill 13\hfill \end{array}\right]\left[\begin{array}{ccc}\hfill 1\hfill & \hfill 0\hfill & \hfill 2\hfill \\ \hfill 0\hfill & \hfill 2\hfill & \hfill 1\hfill \\ \hfill 2\hfill & \hfill 0\hfill & \hfill 3\hfill \end{array}\right]$

$=\left[\begin{array}{ccc}\hfill 5\times 1+0\times 0+8\times 2\hfill & \hfill 5\times 0+0\times 2+8\times 0\hfill & \hfill 5\times 2+0\times 1+8\times 3\hfill \\ \hfill 2\times 1+4\times 0+5\times 2\hfill & \hfill 2\times 0+4\times 2+5\times 0\hfill & \hfill 2\times 2+4\times 1+5\times 3\hfill \\ \hfill 8\times 1+0\times 0+13\times 2\hfill & \hfill 8\times 0+0\times 2+0\times 0\hfill & \hfill 8\times 2+0\times 1+13\times 3\hfill \end{array}\right]$

$\left[\begin{array}{ccc}\hfill 5+16\hfill & \hfill 0\hfill & \hfill 10+24\hfill \\ \hfill 2+10\hfill & \hfill 8\hfill & \hfill 4+4+15\hfill \\ \hfill 8+26\hfill & \hfill 0\hfill & \hfill 16+39\hfill \end{array}\right]$ $=\left[\begin{array}{lll}21\hfill & 0\hfill & 34\hfill \\ 12\hfill & 8\hfill & 23\hfill \\ 34\hfill & 0\hfill & 55\hfill \end{array}\right]$

So, A³-6A² + 7A + 2I

$=\left[\begin{array}{lll}21\hfill & 0\hfill & 34\hfill \\ 12\hfill & 8\hfill & 23\hfill \\ 34\hfill & 0\hfill & 55\hfill \end{array}\right]-6\left[\begin{array}{lll}5\hfill & 0\hfill & 8\hfill \\ 2\hfill & 4\hfill & 5\hfill \\ 8\hfill & 0\hfill & 13\hfill \end{array}\right]+7\left[\begin{array}{lll}1\hfill & 0\hfill & 2\hfill \\ 0\hfill & 2\hfill & 1\hfill \\ 2\hfill & 0\hfill & 3\hfill \end{array}\right]+2\left[\begin{array}{lll}1\hfill & 0\hfill & 0\hfill \\ 0\hfill & 1\hfill & 0\hfill \\ 0\hfill & 0\hfill & 1\hfill \end{array}\right]$

$=\left[\begin{array}{lll}21\hfill & 0\hfill & 34\hfill \\ 12\hfill & 8\hfill & 23\hfill \\ 34\hfill & 0\hfill & 55\hfill \end{array}\right]-\left[\begin{array}{ccc}\hfill 30\hfill & \hfill 0\hfill & \hfill 48\hfill \\ \hfill 12\hfill & \hfill 24\hfill & \hfill 30\hfill \\ \hfill 48\hfill & \hfill 0\hfill & \hfill 78\hfill \end{array}\right]+\left[\begin{array}{ccc}\hfill 7\hfill & \hfill 0\hfill & \hfill 14\hfill \\ \hfill 0\hfill & \hfill 14\hfill & \hfill 7\hfill \\ \hfill 14\hfill & \hfill 0\hfill & \hfill 21\hfill \end{array}\right]+\left[\begin{array}{lll}2\hfill & 0\hfill & 0\hfill \\ 0\hfill & 2\hfill & 0\hfill \\ 0\hfill & 0\hfill & 2\hfill \end{array}\right]$

$=\left[\begin{array}{lll}21-30+7+2\hfill & 0-0+0+0\hfill & 34-48+14+0\hfill \\ 12-12+0+0\hfill & 8-24+14+2\hfill & 23-30+7+0\hfill \\ 34-48+14+0\hfill & 0-0+0+0\hfill & 55-78+21+2\hfill \end{array}\right]$

$=\left[\begin{array}{lll}0\hfill & 0\hfill & 0\hfill \\ 0\hfill & 0\hfill & 0\hfill \\ 0\hfill & 0\hfill & 0\hfill \end{array}\right]=0$ (2000 matrix )

Hence proud

This is a long answer type question as classified in NCERT Exemplar

In group 2, only beryllium is amphoteric in nature which means it reacts with both acids and bases. Also, beryllium only forms covalent oxide due to the covalent nature. So, the element is beryllium.

It reacts with acid to form beryllium chloride and it reacts with base to form beryllate ion which is soluble in sodium hydroxide. The reaction is shown below.

Be (OH)₂+2OH⁻ → [Be (OH)₄]²⁻

Be (OH)₂+2HCl →BeCl₂+2H₂O

IIM waitlist means the number students who are kept waiting for the second shortlist. The institutes select a number of students for admission out of which some miss the first list due to a few points. Such students are kept in waitlist incase any candidate from the first list chooses to not appear for WAT-PI. Those who are kept in the waitlist are invited for WAT-PI if there are seats remaining to be filled after WAT-PI round of the first batch of the students. Also read: IIM Waitlist Movement - Meaning and Past Trends

The median package offered during PSIT College of Higher Education placements over the past three years is presented below:

After the release of CAT result. TAPMI will conduct admission through counselling rounds. Candidates willing to opt for PGDM course must get ready for the admission process at TAPMI. Admission at TAPMI consist of several stages wherein it first release its cutoffs for the MBA courses. After that, students were invited to appear for Written Ability, GD and PI rounds. Then after, institutes shortlist candidates based on their merit results. It is advised for the candidates to keep track of their results. Further, they need to prepare in advance for the GD/PI rounds. Also, they must keep track of the schedule to avoid any rush.

Given, A = $\left[\begin{array}{ccc}\hfill 2\hfill & \hfill 0\hfill & \hfill 1\hfill \\ \hfill 2\hfill & \hfill 1\hfill & \hfill 3\hfill \\ \hfill 1\hfill & \hfill -1\hfill & \hfill 0\hfill \end{array}\right]$

A² = AA² = $\left[\begin{array}{ccc}\hfill 2\hfill & \hfill 0\hfill & \hfill 1\hfill \\ \hfill 2\hfill & \hfill 1\hfill & \hfill 3\hfill \\ \hfill 1\hfill & \hfill -1\hfill & \hfill 0\hfill \end{array}\right]\left[\begin{array}{ccc}\hfill 2\hfill & \hfill 0\hfill & \hfill 1\hfill \\ \hfill 2\hfill & \hfill 1\hfill & \hfill 3\hfill \\ \hfill 1\hfill & \hfill -1\hfill & \hfill 0\hfill \end{array}\right]$

= $\left[\begin{array}{l}2\times 2+0\times 2+1\times 12\times 0+0\times 1+1\times (1)2\times 1+0\times 3+1\times 0\\ 2\times 2+1\times 2+3\times 12\times 0+1\times 1+3\times (-1)2\times 1+1\times 3+3\times 0\\ 1\times 2+(-1)\times 2+0\times 11\times 0+(-1)\times 1+0\times (-1)1\times 1+(-1)\times 3+0\times 0\end{array}\right]$

$=\left[\begin{array}{ccc}\hfill 1+1\hfill & \hfill -1\hfill & \hfill 2\hfill \\ \hfill 4+2+3\hfill & \hfill 1-3\hfill & \hfill 2+3\hfill \\ \hfill 2-2\hfill & \hfill -1\hfill & \hfill 1-3\hfill \end{array}\right]=\left[\begin{array}{ccc}\hfill 5\hfill & \hfill -1\hfill & \hfill 2\hfill \\ \hfill .9\hfill & \hfill -2\hfill & \hfill 5\hfill \\ \hfill 0\hfill & \hfill -1\hfill & \hfill -2\hfill \end{array}\right]$

IIM Ahmedabad, IIM Bangalore and IIM Calcutta have the highest CAT cut off. Every year, the cut off percentiles of these three top IIMs hover around 99-100 percentile. even though the qualifying CAT cut off is lower at 80 or 85 percentile, the final cut offs are the highest among all MBA institutes in India. For, reserved category students the final CAT cut offs of these IIMs are a few percentiles lower. 

PSIT College of Higher Education average package data is not released. However, according to the NIRF report 2025 available, the median package received by BBA and BCA students in 2024 was INR 3.3 LPA.

This is a long answer type question as classified in NCERT Exemplar

Beryllium being least reactive does not form hydride by direct heating with dihydrogen. It is prepared by reacting it with lithium aluminum hydride. The reactions are shown below.

8LiH + Al₂Cl₆→2LiAlH₄+6LiCl

2BeCl₂+LiAlH₄→2BeH₂+LiCl+AlCl₃

This is a long answer type question as classified in NCERT Exemplar

Compound A reacts with water to form compound B. So, the compound A is calcium oxide. When water is added to calcium oxide, calcium hydroxide is formed. It is lime water. The compound gives a milky appearance which is compound C. The compound C is calcium carbonate. On passing, excess carbon dioxide milkiness disappears due to the formation of compound D. The compound is calcium hydrogen carbonate. The reactions are as follows:

CaO+H₂O→Ca (OH)₂

Ca (OH)₂+CO2→CaCO₃

Ca (OH)₂+CO₂+H2O→Ca (HCO₃)₂