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New Question

6 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

HClO4 is the most acidic compound.

New Question

6 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New Question

6 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Correct order of van there Waals constant b for gases is CO2 > N2 > O2 > H2 > He

New Question

6 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Monomer of neoprene polymer is

3-Chloro-1, 3-butadiene

New Question

6 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New Question

6 months ago

0 Follower 38 Views

N
Nitesh Pruthi

Contributor-Level 6

No. The Commission will release the UGC NET notification 2026 for the June session in the form of PDF tentatively in April at ugcnet.nta.nic.in. The registration will also start for the June sesison along with the notification. 

New Question

6 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New Question

6 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

He2 has zero bond order hence it does not exist.

New Question

6 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New Question

6 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kp = Kc (RT)Dng

36 * 10–2 = Kc (0.0821 * 300)–1

Kc = 0.36 * 0.0821 * 300 = 8.86 » 9

New Question

6 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

π 1 = i C R T 1

π 2 = i C R T 2            

π 1 T 1 = π 2 T 2            

π 2 = π 1 * T 2 T 1            

= 7 * 1 0 5 * 2 8 3 2 7 3                  

= 7.256 * 105 * Pa

= 72.56 * 104 Pa

p2 = x * 104

x = 72.56 » 73

New Question

6 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Charge passed = It

= 0.015 × 15 × 60 C

Moles of electrons passed = 0 . 0 1 5 × 1 5 × 6 0 9 6 5 0 0  

Moles of Zn deposited = 1 2 × 0 . 0 1 5 × 1 5 × 6 0 9 6 5 0 0  

= 0.00007

Mass of Zn deposited = 0.00007 × 65.4 g = 4.58mg

New Question

6 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

Thiophene and cysteine contain sulphur atom.

 

New Question

6 months ago

0 Follower 2 Views

New Question

6 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Please find the solution below:

 

 

 

New Question

6 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

B2 have bond order equal to 1 and also paramagnetic.

H e 2 2 + O 2 2 N e 2 2 + F 2 H 2 have bond order equal to 1 but are diamagnetic.

O 2 2 + have bond order equal to 3.

New Question

6 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the image

 

New Question

6 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

Fehling solution test can be given by aldehyde except aromatic aldehyde

can't give Fehling solution test,

other all three given can give Fehling solution test.

 

New Question

6 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

(Ea)net = E a 1 + E a 2 E a 3  

= 40 + 50 – 60

= 90 – 60

= 30kJ/mol

New Question

6 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Please find the solution below:

 

 

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