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4 weeks ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

π 1 = i C R T 1

π 2 = i C R T 2            

π 1 T 1 = π 2 T 2            

π 2 = π 1 * T 2 T 1            

= 7 * 1 0 5 * 2 8 3 2 7 3                  

= 7.256 * 105 * Pa

= 72.56 * 104 Pa

p2 = x * 104

x = 72.56 » 73

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4 weeks ago

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A
alok kumar singh

Contributor-Level 10

Charge passed = It

= 0.015 × 15 × 60 C

Moles of electrons passed = 0 . 0 1 5 × 1 5 × 6 0 9 6 5 0 0  

Moles of Zn deposited = 1 2 × 0 . 0 1 5 × 1 5 × 6 0 9 6 5 0 0  

= 0.00007

Mass of Zn deposited = 0.00007 × 65.4 g = 4.58mg

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4 weeks ago

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A
alok kumar singh

Contributor-Level 10

Thiophene and cysteine contain sulphur atom.

 

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4 weeks ago

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A
alok kumar singh

Contributor-Level 10

Please find the solution below:

 

 

 

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4 weeks ago

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A
alok kumar singh

Contributor-Level 10

B2 have bond order equal to 1 and also paramagnetic.

H e 2 2 + O 2 2 N e 2 2 + F 2 H 2 have bond order equal to 1 but are diamagnetic.

O 2 2 + have bond order equal to 3.

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4 weeks ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the image

 

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4 weeks ago

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A
alok kumar singh

Contributor-Level 10

Fehling solution test can be given by aldehyde except aromatic aldehyde

can't give Fehling solution test,

other all three given can give Fehling solution test.

 

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4 weeks ago

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A
alok kumar singh

Contributor-Level 10

(Ea)net = E a 1 + E a 2 E a 3  

= 40 + 50 – 60

= 90 – 60

= 30kJ/mol

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4 weeks ago

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A
alok kumar singh

Contributor-Level 10

Please find the solution below:

 

 

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4 weeks ago

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A
alok kumar singh

Contributor-Level 10

Assume mass of solution

= 100g

Mass of solute = 36gm

Moles of solute = 1

Molarity=  1 * 1 0 0 0 ( 1 0 0 1 . 5 ) = 1 0 0 0 1 0 0 * 1 . 5 = 1 5

New Question

4 weeks ago

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N
nitesh singh

Contributor-Level 10

After the 2023-24 revised CBSE syllabus, many chapters have been removed, and in some chapters syllabus is reduced. As per the latest CBSE exam pattern 2025-26, the Chapter 1 Solutions will be asked for 5-7 marks in the Class 12 Chemistry CBSE board exams.

For other competitive exams, the Solutions chapter has a medium weightage in the NEET exam. In the NEET exam, 1-2 questions are frequently asked based on the concept of moderate-level numerical.

Physical Chemistry holds over 30% weightage in the chemistry section in the JEE Mains exam. The solutions chapter is considered a part of physical chemistry.  You can expect 1 question fo

...more

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4 weeks ago

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A
alok kumar singh

Contributor-Level 10

37Rb = 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 5s1

Last electron enters in 5s subshell

Value of quantum numbers

n = 5, l = 0, m = 0, s =  ± 1 2

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4 weeks ago

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A
alok kumar singh

Contributor-Level 10

Please find the solution below:

 

 

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4 weeks ago

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A
alok kumar singh

Contributor-Level 10

After balancing change in oxidation state,

2Cl2 2Cl + 2ClO

Next, balance 'O' atoms,

2Cl2 +4OH  2Cl + 2ClO+ 2H2O

Simplifying to get the simplest ratios,

Cl2 +2OH Cl+ClO+ H2O

x = 1, y = 2, z = 1, p = 1

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4 weeks ago

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4 weeks ago

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alok kumar singh

Contributor-Level 10

K2Cr2O7 + H2O2 + H2SO4->  + K2SO4 + H2O compound 'X' is ->CrO5

Oxidation state of chromium = +6.

 

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4 weeks ago

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A
alok kumar singh

Contributor-Level 10

A. Vitamin B12– Co

B.  Wilkinson catalyst –Rh ( [Rh (PPh3)3Cl])

C.  Ziegler-Natta catalyst –Ti (TiCl4 +Al (C2H5)3)

D.  Haemoglobin – Fe

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