3.30. Assign the position of the element having outer electronic configuration,
(i) ns2 np4 for n = 3
(ii) (n – 1) d2 ns2 for n = 4 and
(iii) (n – 2) f7 (n – 1) d1 ns2 for n = 6 in the periodic table?
3.30. Assign the position of the element having outer electronic configuration,
(i) ns2 np4 for n = 3
(ii) (n – 1) d2 ns2 for n = 4 and
(iii) (n – 2) f7 (n – 1) d1 ns2 for n = 6 in the periodic table?
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1 Answer
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3.30. (i) For n = 3, the element belong to 3rd period, p-block element.
The electronic configuration is =1s2 2s2 2p6 3s2 3p4. The element name is sulphur.(ii) For n = 4, the element belongs to 4th period and since the valence shell has 4 electrons it belongs to group 4.
Electronic configuration= 1s2 2s2 2p6 3s2 3p6 3d2 4s2, and the element name is Titanium (Ti).(iii) For n = 6, the element belongs to 6th period. Last electron goes to the f-orbital, element is from f-block. It belongs to group = 3
The element is gadolinium (z = 64)
Complete electronic configuration = [Xe] 4 f7 5...more
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Nuclear Charge: 13/10 12/10 11/10 9/10 8/10 7/10
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(a) The element V has the highest first ionization enthalpy (? iH1) and positive electron gain enthalpy (? egH) and hence it is the least reactive element. Since inert gases have positive? egH, therefore, the element-V must be an inert gas. The values of? iH1, ? iH2 and? egH match that of He.
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