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Chemistry NCERT Exemplar Solutions Class 12th Chapter Eight Chemistry Class 12th Thermodynamics Chemistry NCERT Exemplar Solutions Class 12th Chapter Six

When 5 moles of He gas expand isothermally and reversibly at 300K from 10 litre to 20 litre, the magnitude of the maximum work obtained is___________J. (nearest integer)

[Given: R=8.3 JK^-1mol^-1 and log2 = 0.3010]

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Answered by

Payal Gupta | Contributor-Level 10

3 months ago

Number of moles, n = 5 mol

Temperature, T= 300 K

Initial volume, V₁ = 10L

Final volume, V₂ = 20 L

Using;

Work done; w = -2.303 nRT log₁₀ $\frac{V_{2}}{V_{1}}$

$= - 2.303 \times 5 \times 8 \times 300 l o g_{10} \frac{20}{10} J$

= -8630 J

So, magnitude of work done is 8630 J.

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When 5 moles of He gas expand isothermally and reversibly at 300K from 10 litre to 20 litre, the magnitude of the maximum work obtained is___________J. (nearest integer)

[Given: R=8.3 JK^-1mol^-1 and log2 = 0.3010]

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When 5 moles of He gas expand isothermally and reversibly at 300K from 10 litre to 20 litre, the magnitude of the maximum work obtained is___________J. (nearest integer) [Given: R=8.3 JK-1mol-1 and log2 = 0.3010]

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When 5 moles of He gas expand isothermally and reversibly at 300K from 10 litre to 20 litre, the magnitude of the maximum work obtained is___________J. (nearest integer)

[Given: R=8.3 JK^-1mol^-1 and log2 = 0.3010]