When BCl3 is treated with water, it hydrolyses and forms [B(OH)4]−only whereas AlCl3 in acidified aqueous solution forms [Al(H20)6]3+
Explain what is the hybridisation of boron and aluminium in these species?
When BCl3 is treated with water, it hydrolyses and forms [B(OH)4]−only whereas AlCl3 in acidified aqueous solution forms [Al(H20)6]3+
Explain what is the hybridisation of boron and aluminium in these species?
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1 Answer
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This is a Short Answers Type Questions as classified in NCERT Exemplar
BCl3+3H2O→B (OH)3+3HCl
B (OH)3+2H2O→ [B (OH)4]−+H3O+
B (OH)3 due to its incomplete octet accepts an electron pair (OH)- to give has configucation [B (OH)4]−.
Boron in this ion involves one 2s orbital and three 2p orbitals. Thus, hybridization of B in [B (OH)4]− is sp3
AlCl3 + 6H2O [Al (H2O)6]3+ +3Cl-
Hence, hybridization of Al is sp3d2
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