When BCl3 is treated with water, it hydrolyses and forms [B(OH)4]−only whereas AlCl3 in acidified aqueous solution forms [Al(H20)6]3+ Explain what is the hybridisation of boron and aluminium in these species?

This is a Short Answers Type Questions as classified in NCERT Exemplar BCl3+3H2O→B (OH)3+3HCl B (OH)3+2H2O→ [B (OH)4]−+H3O+ B (OH)3 due to its incomplete octet accepts an electron pair (OH)- to give has configucation [B (OH)4]−. Boron in this ion involves one 2s orbital and three 2p orbitals. Thus, hybridization of B in [B (OH)4]− is sp3 AlCl3 + 6H2O [Al (H2O)6]3+ +3Cl- Hence, hybridization of Al is sp3d2

When BCl₃ is treated with water, it hydrolyses and forms [B(OH)₄]⁻only whereas AlCl₃ in acidified aqueous solution forms [Al(H₂0)₆]³⁺

Explain what is the hybridisation of boron and aluminium in these species?

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Alok Kumar Singh | Contributor-Level 10

8 months ago

This is a Short Answers Type Questions as classified in NCERT Exemplar

BCl₃+3H₂O→B (OH)₃+3HCl

B (OH)₃+2H₂O→ [B (OH)₄]⁻+H₃O⁺

B (OH)₃due to its incomplete octet accepts an electron pair (OH)^- to give has configucation [B (OH)₄]⁻.

Boron in this ion involves one 2s orbital and three 2p orbitals. Thus, h

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Match the species given in Column I with the properties mentioned in Column II.

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Chemistry NCERT Exemplar Solutions Class 11th Chapter Eleven 2025

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(i) Boron in [B(OH)₄]⁻	(a) sp²
(ii) Aluminium in [Al(H₂O)₆]³⁺	(b) sp³
(iii) Boron in B₂H₆	(c) sp³d²
(iv) Carbon in Buckminsterfullerene
(v) Silicon in SiO₄⁴⁻
(vi) Germanium in [GeCl₆]²⁻

Column I	Column II
(i) Diborane	(a) Used as a flux for soldering metals
(ii) Gallium	(b) Crystalline form of silica
(iii) Borax	(c) Banana bonds
(iv) Aluminosilicate	(d) Low melting, high boiling, useful for measuring high temperatures
(v) Quartz	(e) Used as catalyst in petrochemical industries.

Column I	Column II
(i) BF₄⁻	(a) Oxidation state of central atom is +4
(ii) AlCl₃	(b) Strong oxidising agent
(iii) SnO	(c) Lewis acid
(iv) PbO₂	(d) Can be further oxidised
	(e) Tetrahedral shape