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38. Reduce the following equations into intercept form and find their intercepts onthe axes.

(i) 3x + 2y – 12 = 0, (ii) 4x – 3y = 6, (iii) 3y + 2 = 0.

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alok kumar singh | Contributor-Level 10

4 months ago

38. (i) Given, 3x + 2y 12 = 0.

3x + 2y = 12

Dividing both sides by 12 we get,

$\Rightarrow \frac{3 x}{12} + \frac{2 y}{12} = \frac{12}{12}$

$\Rightarrow \frac{x}{4} + \frac{y}{6} = 1 .$

Comparing the above equation with $\frac{x}{a} + \frac{y}{b} = 1$ = we get, x-intercept, a = 4 and y-intercept b = 6.

(ii) Given, 4x - 3y = 6

Dividing the both sides by 6.

$\frac{4 x}{6} - \frac{3 y}{6} = \frac{6}{6}$

$\Rightarrow \frac{2 x}{3} - \frac{y}{2} = 1$

$\Rightarrow \frac{x}{3 / 2} + \frac{y}{(- 2)} = 1 .$

Comparing above equation by $\frac{x}{a} + \frac{y}{b} = 1$ we get, x-intercept a = $\frac{3}{2}$ and y-intercept, b = -2

(iii) Given, 3y + 2 = 0.

3y = -2

$y = - \frac{2}{3}$

As the equation of line is of form y = constant, it is parallel to x-axis and has no x-intercept.

y-intercept = - $\frac{2}{3}$

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Answered by

alok kumar singh | Contributor-Level 10

4 months ago

38.

(i) Given, 3x + 2y 12 = 0.

3x + 2y = 12

Dividing both sides by 12 we get,

$\Rightarrow \frac{3 x}{12} + \frac{2 y}{12} = \frac{12}{12}$

$\Rightarrow \frac{x}{4} + \frac{y}{6} = 1 .$

Comparing the above equation with $\frac{x}{a} + \frac{y}{b} = 1$ = we get, x-intercept, a = 4 and y-intercept b = 6.

(ii) Given, 4x - 3y = 6

Dividing the both sides by 6.

$\frac{4 x}{6} - \frac{3 y}{6} = \frac{6}{6}$

$\Rightarrow \frac{2 x}{3} - \frac{y}{2} = 1$

$\Rightarrow \frac{x}{3 / 2} + \frac{y}{(- 2)} = 1 .$

Comparing above equation by $\frac{x}{a} + \frac{y}{b} = 1$ we get, x-intercept a = $\frac{3}{2}$ and y-intercept, b = -2

(iii) Given, 3y + 2 = 0.

3y = -2

$y = - \frac{2}{3}$

As the equation of line is of form y = constant, it is parallel to x-axis and has no x-intercept.

y-intercept = - $\frac{2}{3}$

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38. Reduce the following equations into intercept form and find their intercepts onthe axes.

(i) 3x + 2y – 12 = 0, (ii) 4x – 3y = 6, (iii) 3y + 2 = 0.

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38. Reduce the following equations into intercept form and find their intercepts onthe axes. (i) 3x + 2y – 12 = 0, (ii) 4x – 3y = 6, (iii) 3y + 2 = 0.

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38. Reduce the following equations into intercept form and find their intercepts onthe axes.

(i) 3x + 2y – 12 = 0, (ii) 4x – 3y = 6, (iii) 3y + 2 = 0.