73. Find equation of the line which is equidistant from parallel lines 9x + 6y – 7 = 0 and 3x + 2y + 6 = 0.
73. Find equation of the line which is equidistant from parallel lines 9x + 6y – 7 = 0 and 3x + 2y + 6 = 0.
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1 Answer
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73. The given eqn of limes are.
9x + 6y – 7 = 0 ______ (1)
3x + 2y + b = 0 ______ (2)
Let P (x0, y0) be a point equidistant from (1) and (2) so
9x0 + 6y - 7 = ± 3 (3x0 + 2y0 + 6)
When, 9x0 + 6y0 – 7 = 3 (3x0 + 2y0 + 6)
⇒ 9x0 + 6y0 - 7 = 9x0 + 6y0 + 18
⇒ - 7 = 18 which in not true
So, 9x0 + 6y0 - 7 = -3 (3x0 + 2y0 + 6)
⇒ 9x0 + 6y0 -7 = -9x0 -6y0 -18
⇒ 18x0 + 12y0 + 11= 0.
Hence, the required eqn of line through (x0, y0) & equidistant from parallel line 9x + 6y - 7 = 0
and 3x + 2y + 6 = 0 is 18x + 12y + 11 = 0.
Similar Questions for you
Eqn : y – 0 = tan45° (x – 9) Þ y = (x – 9)
Option (B) is correct
|r1 – r2| < c1c2 < r1 + r2
->
Now,
(y – 2) = m (x – 8)
⇒ x-intercept
⇒
⇒ y-intercept
⇒ (–8m + 2)
⇒ OA + OB =
->
->
->
->Minimum = 18
Kindly consider the following figure
According to question,
Equation of required line is
Obviously B (2, 2) satisfying condition (i)
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