11.36 Compute the typical de Broglie wavelength of an electron in a metal at 27 °C and compare it with the mean separation between two electrons in a metal which is given to be about 2 × 10–10 m.

[Note: Exercises 11.35 and 11.36 reveal that while the wave-packets associated with gaseous molecules under ordinary conditions are non-overlapping, the electron wave-packets in a metal strongly overlap with one another. This suggests that whereas molecules in an ordinary gas can be distinguished apart, electrons in a metal cannot be distinguished apart from one another. This indistinguishibility has many fundamental implications which you will explore in more advanced Physics courses.]

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    Payal Gupta | Contributor-Level 10

    4 months ago

    11.36 Temperature, T = 27 ?  = 300 K

    Mean separation between two electrons, r = 2 × 10 - 10  m

    De Broglie wavelength of an electron is given as:

    λ = h 3 m k T , where

    Planck’s constant, h = 6.626 × 10 - 34  Js

    m = mass of an electron = 9.11 × 10 - 31  kg

    k = Boltzmann constant = 1.38 × 10 - 23  J m o l - 1 K - 1

    λ = 6.626 × 10 - 34 3 × 9.11 × 10 - 31 × 1.38 × 10 - 23 × 300 = 6.23 × 10 - 9  m

    Hence, the De Broglie wavelength is much greater than the given inter-electron separation.

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