11.6 In an experiment on photoelectric effect, the slope of the cut-off voltage versus frequency of incident light is found to be 4.12 *10-15 Vs. Calculate the value of Planck's constant.

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11. The slope of the cut-off voltage (V) versus frequency ( ν) of an incident light is given as:

Vν= 4.12 *10-15 Vs

The relationship of V and ν is given as hν = eV or Vν= he

where e = Charge of an electron = 1.6 *10-19 C and h = Plank's constant

Therefore, h = e*Vν = 1.6 *10-19 * 4.12 *10-15 = 6.592 *10-34 Js

Plank's constant = 6.592 *10-34 Js

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This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

f(x)=2x23x2x2=2x24x+x2x2=2x(x2)+1(x2)x2=(2x+1)(x2)x2=2x+1limx2f(x)=2x+1=limh02(2h)+1=4+1=5limx2+f(x)=2x+1=limh02(2+h)+1=4+1=5limx2f(x)=5Aslimx2f(x)=limx2+f(x)=limx2f(x)=5Hence,f(x)iscontinuousatx=2.

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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