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3.10 A player throws a ball upwards with an initial speed of 29.4 m s–1.

(a) What is the direction of acceleration during the upward motion of the ball?

 

(b) What are the velocity and acceleration of the ball at the highest point of its motion?

 

(c) Choose the x = 0 m and t = 0 s to be the location and time of the ball at its highest point, vertically downward direction to be the positive direction of x axis, and give the signs of position, velocity and acceleration of the ball during its upward, and downward motion

 

(d) To what height does the ball rise and after how long does the ball return to the player’s hands? (Take g = 9.8 m s–2 and neglect air resistance)

0 468 Views | Posted 5 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    3 months ago

    3.10

    (a) The direction of the acceleration is downward during the upward motion of the ball because the acceleration is due to gravity. Gravity always pulls the object toward the centre of the earth. 

    (b) Velocity: At the peak the velocity is zero because the ball momentarily stops before falling downwards. 

    Acceleration: g = 9.8 ms–2

    (c) If we consider the highest point x = 0 m, t= 0 s,

    During upward motion of the ball before it reaches the maximum height, x = +ve, velocity = -ve, acceleration = +ve. During downward motion, x = +ve, velocity = +ve, acceleration = +ve

    (d) At the highest point, final velocity v = 0, initial

    ...more

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