3.7 Two trains A and B of length 400 m each are moving on two parallel tracks with a uniform speed of 72 km h–1 in the same direction, with A ahead of B. The driver of B decides to overtake A and accelerates by 1 m s–2. If after 50 s, the guard of B just brushes past the driver of A, what was the original distance between them?

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8 months ago

3.7 The uniform speed of A and B = 72 kmph = 20 m/s

The acceleration f = 1 m/s2, time t = 50 s

Distance covered by train B = ut + 0.5 * ft= 20 * 50 + 0.5 * 1 * 50 2 = 2250 m

Distance covered by train A in the same period = ut = 50 * 20 = 1000 m

So the initial distance train A and train B was = 2250 –

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(d) Initial velocity  = - v j ˆ

Final velocity = v i ˆ

Change in velocity  = v i ˆ - ( - v j ˆ )

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physics ncert solutions class 11th 2023

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