4.11 A passenger arriving in a new town wishes to go from the station to a hotel located 10 km away on a straight road from the station. A dishonest cabman takes him along a circuitous path 23 km long and reaches the hotel in 28 min. What is (a) the average speed of the taxi (b) the magnitude of average velocity? Are the two equal?

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Vishal Baghel | Contributor-Level 10

5 months ago

4.11

(a) Total distance travelled = 23 km, Total time taken = 28 min

Average speed = $\frac{T o t a l d i s t a n c e t r a v e l l e d}{T o t a l t i m e t a k e n}$ = $\frac{23}{28}$ km/min = 49.29 km/h

(b) Average velocity = $\frac{T o t a l d i s p l a c e m e n t}{t o t a l t i m e t a k e n}$ = $\frac{10}{28}$ km/min = 21.43 km/h

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