physics ncert solutions class 11th Physics Class 11th Laws of Motion

5.14 Figure 5.16 shows the position-time graph of a particle of mass 4 kg. What is the

(a) Force on the particle for t < 0, t > 4 s, 0 < t < 4 s?

(b) Impulse at t = 0 and t = 4 s? (Consider one-dimensional motion only)

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1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

4 months ago

(a) For t<0, the distance covered by the particle x is zero. Hence force on the particle is zero. For t>4s, the particle is moving at a constant distance, so the force will be zero. For 0

(b) Impulse is given by the equation, Impulse = total change of momentum. At t = 0, u = 0, v = distance / time = ¾ = 0.75 m/s

Impulse = 4 $*$ (0.75-0) kg-m/s = 3 kg-m/s

Impulse at t=4, u = 0.75, v = 0, Impulse = 4 (0-0.75) = -3 kgm/s

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