5.15 Two bodies of masses 10 kg and 20 kg respectively kept on a smooth, horizontal surface are tied to the ends of a light string. A horizontal force F = 600 N is applied to (i) A, (ii) B along the direction of string. What is the tension in the string in each case?

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Answered by

Vishal Baghel | Contributor-Level 10

4 months ago

Mass of the body A, m₁ = 10 kg, mass of the body B, m₂ = 20 kg, Horizontal force = 600 N

Total mass of the system, m =m₁ + m₂ = 30 kg

From the relation F = ma, we get a = 600 / 30 = 20 m/s²

(i) When the force is applied on A

F – T = m₁a or T = F - m₁a = 600 – 10 $* 20$ = 400 N

(ii) When the force is applied on B

F-T = m₂a, T = F - m₂a = 600 – 20 $* 20 = 200$ N

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