5.18 Two billiard balls each of mass 0.05 kg moving in opposite directions with speed 6 m s-1collide and rebound with the same speed. What is the impulse imparted to each ball due to the other?

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5.18 Two billiard balls each of mass 0.05 kg moving in opposite directions with speed 6 m s^-1collide and rebound with the same speed. What is the impulse imparted to each ball due to the other?

25 Views | Posted 4 months ago

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Answered by

Vishal Baghel | Contributor-Level 10

4 months ago

Mass of each ball, m = 0.05 kg

Initial velocity of each ball, u = 6 m/s

The initial momentum of each ball before collision = mu = 0.05 x 6 = 0.3 kg-m/s

After the collision, the ball changes the direction of motion without the change in magnitude of the velocity, so

The final momentum after collision of the first ball = - 0.05 $*$ 6 = - 0.3 kg-m/s

The final momentum after collision of the second ball = 0.05 $*$ 6 = 0.3 kg-m/s

Impulse imparted to the first ball = (-0.3) – (0.3) = -0.6 kg-m/s

Impulse imparted to the second ball = (0.3) – (-0.3) = 0.6 kg-m/s

The two impulses are opposite in direction.

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