5.35 A block of mass 15 kg is placed on a long trolley. The coefficient of static friction between the block and the trolley is 0.18. The trolley accelerates from rest with 0.5 m s-2 for 20 s and then moves with uniform velocity.
Discuss the motion of the block as viewed by
(a) A stationary observer on the ground
(b) An observer moving with the trolley
5.35 A block of mass 15 kg is placed on a long trolley. The coefficient of static friction between the block and the trolley is 0.18. The trolley accelerates from rest with 0.5 m s-2 for 20 s and then moves with uniform velocity.
Discuss the motion of the block as viewed by
(a) A stationary observer on the ground
(b) An observer moving with the trolley
Mass of the block = 15 kg
Coefficient of static friction between the block and the trolley = 0.18
Acceleration of the trolley = 0.5 m/s2
(a) Force experienced by block, F = MA = 15 0.5 = 7.5 N. This fore acts in the direction of motion of the trolley
Force of friction, Ff = = 0.18 N = 27 N
Force ex
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= 0.92 * 1260 = 1161 m/s
For 2 kg block
T – 2g sin37 = 2a . (i)
For 4 kg block
4g – 2T =
2g – T = a . (ii)
T = (2g – a)
2g – a – 2g × = 2a
3a = 2g ×
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physics ncert solutions class 11th 2023
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