5.36 The rear side of a truck is open and a box of 40 kg mass is placed 5 m away from the open end as shown in Fig. 5.22. The coefficient of friction between the box and the surface below it is 0.15. On a straight road, the truck starts from rest and accelerates with 2 m s-2. At what distance from the starting point does the box fall off the truck? (Ignore the size of the box).

5.36 The rear side of a truck is open and a box of 40 kg mass is placed 5 m away from the open end as shown in Fig. 5.22. The coefficient of friction between the box and the surface below it is 0.15. On a straight road, the truck starts from rest and accelerates with 2 m s-2. At what distance from the starting point does the box fall off the truck? (Ignore the size of the box).

Force on the box, F = MA = 40 2 N = 80 N
Frictional force, Ff = = 0.15 60 N
Net force = F – Ff = 80 – 60 = 20 N
From the equation F = ma, we get the backward acceleration produced in the box
a = 20/40 = 0.5 m/s2
From the equation s = ut + , to travel s = 5 m by the box to fall off from the truck, we
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3a = 2g ×
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physics ncert solutions class 11th 2023
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