5.39 A 70 kg man stands in contact against the inner wall of a hollow cylindrical drum of radius 3 m rotating about its vertical axis with 200 rev/min. The coefficient of friction between the wall and his clothing is 0.15. What is the minimum rotational speed of the cylinder to enable the man to remain stuck to the wall (without falling) when the floor is suddenly removed ?
5.39 A 70 kg man stands in contact against the inner wall of a hollow cylindrical drum of radius 3 m rotating about its vertical axis with 200 rev/min. The coefficient of friction between the wall and his clothing is 0.15. What is the minimum rotational speed of the cylinder to enable the man to remain stuck to the wall (without falling) when the floor is suddenly removed ?

Mass of the man, m = 70 kg
Radius of the drum, r = 3 m
Coefficient of friction between the wall and his clothing, = 0.15
Number of revs of hollow cylindrical drum = 200 rev/min = 200/60 rev/s = 3.33 rev/s
The centripetal force required is provided by the normal N of the wall on the man
N = m = m R
Whe
Similar Questions for you
= 0.92 * 1260 = 1161 m/s
For 2 kg block
T – 2g sin37 = 2a . (i)
For 4 kg block
4g – 2T =
2g – T = a . (ii)
T = (2g – a)
2g – a – 2g × = 2a
3a = 2g ×
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
Learn more about...

physics ncert solutions class 11th 2023
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
See what others like you are asking & answering





