7.10 (a) Find the moment of inertia of a sphere about a tangent to the sphere, given the moment of inertia of the sphere about any of its diameters to be 2MR 2/5, where M is the mass of the sphere and R is the radius of the sphere.

(b) Given the moment of inertia of a disc of mass M and radius R about any of its diameters to be MR 2/4, find its moment of inertia about an axis normal to the disc and passing through a point on its edge.

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    Answered by

    Vishal Baghel | Contributor-Level 10

    4 months ago

    (a)

    The moment of Inertia of a sphere about its diameter = 2MR 2/5

    According to the theorem of parallel axis, the moment of inertia of a body about any axis is equal to the sum of the moment of inertia of the body about a parallel axis passing through its centre of mass and the product of its mass and square of the distance between two parallel axes

    Hence the moment of inertia about a tangent of the sphere = 2MR 2/5 + MR2 = 7MR 2/5

     

    (b)

    The moment of inertia of a disc about its diameter = MR 2/4

    According to the theorem of perpendicular axis, the moment of inertia of a planar body about an axis perpendicular to its plane is equal to t

    ...more

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