7.19 A hoop of radius 2 m weighs 100 kg. It rolls along a horizontal floor so that its centre of mass has a speed of 20 cm/s. How much work has to be done to stop it?
7.19 A hoop of radius 2 m weighs 100 kg. It rolls along a horizontal floor so that its centre of mass has a speed of 20 cm/s. How much work has to be done to stop it?
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1 Answer
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Radius of the hoop, r = 2 m, mass of the hoop, m = 100 kg, velocity of the hoop, v = 20 cm /s = 0.2 m/s
Total energy of the hoop = Translational KE + Rotational KE = m +
Moment of inertia about the centre, I = mr2
So the total energy = m +
Since v = r we get
Total energy = m + =
Required work to be done = 100 x 0.2 x 0.2 J = 4 J
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