7.20 The oxygen molecule has a mass of 5.30 * 10-26 kg and a moment of inertia of 1.94*10-46 kg m2 about an axis through its centre perpendicular to the lines joining the two atoms. Suppose the mean speed of such a molecule in a gas is 500 m/s and that its kinetic energy of rotation is two thirds of its kinetic energy of translation. Find the average angular velocity of the molecule.
7.20 The oxygen molecule has a mass of 5.30 * 10-26 kg and a moment of inertia of 1.94*10-46 kg m2 about an axis through its centre perpendicular to the lines joining the two atoms. Suppose the mean speed of such a molecule in a gas is 500 m/s and that its kinetic energy of rotation is two thirds of its kinetic energy of translation. Find the average angular velocity of the molecule.
Mass of the oxygen molecule, m = 5.30 * 10-26 kg
Moment of inertia, I = 1.94*10-46 kg m2
Velocity of the oxygen molecule, v = 500 m/s
the separation of atoms in oxygen molecule = 2r.
the mass of each oxygen atom = (m/2)
Moment of inertia I can be calculated as I = (m/2)r2 + (m/2)r2
hence r =
r = sqrt (1
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Use formula for M.I.
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physics ncert solutions class 11th 2023
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