7.9 A car weighs 1800 kg. The distance between its front and back axles is 1.8 m. Its centre of gravity is 1.05 m behind the front axle. Determine the force exerted by the level ground on each front wheel and each back wheel.
7.9 A car weighs 1800 kg. The distance between its front and back axles is 1.8 m. Its centre of gravity is 1.05 m behind the front axle. Determine the force exerted by the level ground on each front wheel and each back wheel.

Mass of the car, m = 1800 kg
Distance between the front and rear axles, d = 1.8 m
Distance between C.G. and the front axle = 1.05 m
Let Rf and Rb be the force exerted from ground at front and rear axles respectively.
Rf + Rb = mg = 1800 x 9.8 N = 17640 N ……. (i)
For rotational equilibrium around C.G. we
Similar Questions for you
Use formula for M.I.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
Learn more about...

physics ncert solutions class 11th 2023
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
See what others like you are asking & answering


