7.9 A car weighs 1800 kg. The distance between its front and back axles is 1.8 m. Its centre of gravity is 1.05 m behind the front axle. Determine the force exerted by the level ground on each front wheel and each back wheel.

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Answered by

Vishal Baghel | Contributor-Level 10

4 months ago

Mass of the car, m = 1800 kg

Distance between the front and rear axles, d = 1.8 m

Distance between C.G. and the front axle = 1.05 m

Let Rf and Rb be the force exerted from ground at front and rear axles respectively.

Rf + Rb = mg = 1800 x 9.8 N = 17640 N ……. (i)

For rotational equilibrium around C.G. we have Rf x 1.05 = Rb x (1.8 – 1.05)

R_f x 1.05 = R_b x 0.75

R_f/R_b = 0.75 / 1.05

R_f = 0.71 R_b ……. (ii)

From equation (i), we get

0.71 R_b + R_b = 17640

R_b = 10316 N

R_f = 7324 N

Therefore, force exerted on each front wheel = R_f/2 =7324/2 = 3662 N

Force exerted on each rear wheel, R_b/2 = 10316 / 2= 5158 N

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