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A 10μF capacitor is fully charged to a potential difference of 50 V. After removing the source voltage, it is connected to an uncharged capacitor in parallel. Now the potential difference across them becomes 20 V. The capacitance of the second capacitor is:

Option 1 -

15μF

Option 2 -

20μF

Option 3 -

10μF

Option 4 -

30μF

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago
    Correct Option - 1


    Detailed Solution:

    By conservation of charge, (50) (10) = 20 (10+C) ⇒ C=15µF

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