A 10μF capacitor is fully charged to a potential difference of 50 V. After removing the source voltage, it is connected to an uncharged capacitor in parallel. Now the potential difference across them becomes 20 V. The capacitance of the second capacitor is:
A 10μF capacitor is fully charged to a potential difference of 50 V. After removing the source voltage, it is connected to an uncharged capacitor in parallel. Now the potential difference across them becomes 20 V. The capacitance of the second capacitor is:
Option 1 -
15μF
Option 2 -
20μF
Option 3 -
10μF
Option 4 -
30μF
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1 Answer
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Correct Option - 1
Detailed Solution:By conservation of charge, (50) (10) = 20 (10+C) ⇒ C=15µF
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