A ball is thrown up vertically with a certain velocity so that, it reaches a maximum height h. Find the ratio of the times in which it is at height while going up and coming down respectively.
A ball is thrown up vertically with a certain velocity so that, it reaches a maximum height h. Find the ratio of the times in which it is at height while going up and coming down respectively.
Option 1 -
Option 2 -
Option 3 -
Option 4 -
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1 Answer
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Correct Option - 2
Detailed Solution:
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Let 't' be the time taken by B to meat A.
for A, u = 0
t = [2 + t]
h = 80m
a = 10 m/sec2
h = ut +
80 = 0 * t +
t + 2 = 4
t = 2sec
Now for B
h = ut +
Let ‘t’ be the time taken by B to meat

A.
for A, u = 0
t = [2 + t]
h = 80m
a = 10 m/sec2
h = ut +
80 = 0 × t +
16 = (2 + t)2
t + 2 = 4
t = 2sec
Now for B
h = ut +
80 = 2u + 5 × 2 × 2
80 = 2u + 20
2u = 60
u = 30m/sec
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