A calorimeter of water equivalent 20 g  contains 180 g of water at 25 ? C , ' m  ' grams of steam at   100 ? C is mixed in it till the temperature of the mixture is 31 ? C   . The value of

 

Option 1 -

2.6

Option 2 -

4

Option 3 -

2

Option 4 -

3.2       

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago
    Correct Option - 3


    Detailed Solution:

    Heat lost by steam =  Heat gained by water and calorimeter.

    m × 540 + m × 1 × ( 100 - 31 ) = 200 540 m + 69 m = 1200 m = 1200 609 2

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