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Thermodynamic Process Physics Thermodynamics Physics Class 11th

The amount of heat needed to raise the temperature of 4 moles of a rigid diatomic gas from 0°C to 50°C when no work is done is___________. (R is the universal gas constant)

Option 1 -

175 R

Option 2 -

750 R

Option 3 -

250 R

Option 4 -

500 R

2 Views | Posted 2 months ago

Asked by Shiksha User

1 Answer

Answered by

alok kumar singh | Contributor-Level 10

2 months ago

Correct Option - 4

Detailed Solution:

Since process is isochoric, so

$Q = n C_{v} Δ T = n (\frac{f}{2} R) Δ T = 4 (\frac{5}{2} \times R) (50) = 500 R$

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A calorimeter of water equivalent $20 g$ contains $180 g$ of water at $25^{?} C$ , ' $m$ ' grams of steam at $100^{?} C$ is mixed in it till the temperature of the mixture is $31^{?} C$ . The value of

alok kumar singh

Heat lost by steam $=$ Heat gained by water and calorimeter.

$\begin{array}{r} m \times 540 + m \times 1 \times (100 - 31) = 200 \\ 540 m + 69 m = 1200 \\ m = \frac{1200}{609} \approx 2 \end{array}$

Match List I with List II.

List I List II

(a) Isothermal (i) Pressure constant

(b) Isochoric (ii) Temperature constant

(c) Adiabatic (iii) Volume constant

(d) Isobaric (iv) Heat content is constant

Choose the correct answer from the options given below:

alok kumar singh

In isothermal process, temperature is constant.

In isochoric process, volume is constant.

In adiabatic process, there is no exchange of heat.

In isobaric process, pressure is constant

The entropy of any system is given by S = $α^{2} β l n [\frac{μ k R}{J β^{2}} + 3]$ Where a and b are the constants. $μ$ , J, k and R no. of moles, mechanical equivalent of heat, Bolzmann constant and gas constant respectively. $[T a k e S = \frac{d Q}{T}]$

Choose the incorrect option from the following:

alok kumar singh

N_a -> Avogadro’s Number

$J β^{2} \equiv [μ k R] \Rightarrow β^{2} \equiv [k R] \Rightarrow β \equiv [k] \equiv [M L^{2} T^{- 2} K^{- 1}]$

, and

-> $S \equiv α^{2} β \Rightarrow [M L^{2} T^{- 2} K^{- 1}] \equiv α^{2} [M L^{2} T^{- 2} K^{- 1}] \Rightarrow α \equiv [M^{0} L^{2} T^{0} K^{0}]$ Dimensionless

In the reported figure, hear energy absorbed by a system in going through a cyclic process is_______ pJ.

alok kumar singh

Heat absorbed in cyclic process = Work done = 100? Joule

The temperature of 3.00 mol of an ideal diatomic gas in increased by 40.0°C without changing the pressure of the gas. The molecules in the gas rotate but do not oscillate. If the ratio of change in internal energy of the gas to the amount of work done by the gas is $\frac{x}{10} .$ Then the value of x (round off to the nearest integer) is________.

(Given R = 8.31 J mol^-1K^-1)

alok kumar singh

Since process is isochoric

So $Δ U = n C_{v} Δ T$

$Δ U = n (\frac{5}{2} R) Δ T - - (i) [C_{V} = \frac{5}{2} R]$

And external work

$Δ W = n R Δ T - - (i i)$

$\frac{5}{2} = \frac{x}{10} \Rightarrow x = 25.00$

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The amount of heat needed to raise the temperature of 4 moles of a rigid diatomic gas from 0°C to 50°C when no work is done is___________. (R is the universal gas constant)

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