A graph of x versus t is shown in Fig Choose correct alternatives from below. (a) The particle was released from rest at t = 0. (b) At B, the acceleration a > 0. (c) At C, the velocity and the acceleration vanish. (d) Average velocity for the motion between A and D is positive. (e) The speed at D exceeds that at E.
This is a multiple choice answer as classified in NCERT Exemplar
(a, c, d) at point A graph will parallel to time axis hence, v=dx/dt=0. As the starting point is A hence, we can say that the particle is starting from rest.
At C, the graph changes slope, hence velocity also changes. As graph at C is almost parallel to time axis hence, we can say that velocity vanishes.
Velocity is 0. So particle at rest that time. As slope of D will be greater than E . so velocity will be greater at D.
<p><span data-teams="true">This is a multiple choice answer as classified in NCERT Exemplar</span></p><p> (a, c, d) at point A graph will parallel to time axis hence, v=dx/dt=0. As the starting point is A hence, we can say that the particle is starting from rest.</p><p>At C, the graph changes slope, hence velocity also changes. As graph at C is almost parallel to time axis hence, we can say that velocity vanishes.</p><p>Velocity is 0. So particle at rest that time. As slope of D will be greater than E . so velocity will be greater at D.</p>
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