A particle is projected in air at some angle to the horizontal, moves along parabola as shown in Fig., where x and y indicate horizontal and vertical directions, respectively. Show in the diagram, direction of velocity and acceleration at points A, B and C.
This is a Short Answer Type Question as classified in NCERT Exemplar
Explanation- vsin= vertical component
Vx= horizontal component of velocity =vcos= constant
Vy = vertical component of velocity =vsin
Velocity will always be tangential to the curve in the direction of motion and acceleration is always vertically downward and is equal to g.
<p>This is a Short Answer Type Question as classified in NCERT Exemplar</p><p><strong>Explanation</strong>- vsin<span contenteditable="false"> <math> <mi>θ</mi> <mi> </mi> </math> </span>= vertical component</p><div><div><picture><source srcset="https://images.shiksha.com/mediadata/images/articles/1745402557php2s7qua_480x360.jpeg" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/articles/1745402557php2s7qua.jpeg" alt="" width="238" height="161"></picture></div><div><p>V<sub>x</sub>= horizontal component of velocity =vcos<span contenteditable="false"> <math> <mi>θ</mi> </math> </span>= constant</p><p>V<sub>y</sub> = vertical component of velocity =vsin<span contenteditable="false"> <math> <mi>θ</mi> </math> </span></p><p>Velocity will always be tangential to the curve in the direction of motion and acceleration is always vertically downward and is equal to g.</p></div></div>
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