A sinusoidal wave y(t) = 40 sin (10 × 106pt) is amplitude modulated by another sinusoidal wave x(t) = 20sin(1000πt). The amplitude of minimum frequency component of modulated signal is:
A sinusoidal wave y(t) = 40 sin (10 × 106pt) is amplitude modulated by another sinusoidal wave x(t) = 20sin(1000πt). The amplitude of minimum frequency component of modulated signal is:
Option 1 -
0.5
Option 2 -
0.25
Option 3 -
20
Option 4 -
10
-
1 Answer
-
Correct Option - 4
Detailed Solution:So amplitude of minimum frequency =
= 10
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According to question, we can write
Increment in height of tower = h2 – h1 = 500 – 125 = 375 m
Low pass filter will allow low frequency signal to pass while high pass filter allow high frequency to pass through
µ = A? /A? = 0.5 {A? = 20 volt, A? = 40 volt}
m (t) = A? sin ω? t {ω? = 2π×10? }
c (t) = A? sin ω? t {ω? = 2π×10×10³}
C? (t) = (A? + A? sin ω? t) sin ω? t ⇒ A? {1+ µsin ω? t} sin ω? t
Kindly consider the following figure
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