A signal containing multiple frequencies is shown in figure A. It is passed through 2 different filters and then outputs are shown in figure B & C.

Option 1 -

B corresponds to low pass filter and C to high pass filter.

Option 2 -

B corresponds to high pass filter and C to low pass filter.

Option 3 -

Both correspond to low pass filter

Option 4 -

Both correspond to high pass filter.

0 1 View | Posted 3 weeks ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    3 weeks ago
    Correct Option - 1


    Detailed Solution:

    Low pass filter will allow low frequency signal to pass while high pass filter allow high frequency to pass through

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V
Vishal Baghel

According to question, we can write

  d = 2 h R d 2 d 1 = h 2 h 1 h 2 = ( d 2 d 1 ) 2 h 1 = ( 2 1 ) 2 × 1 2 5 = 5 0 0 m

Increment in height of tower = h2 – h1 = 500 – 125 = 375 m

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λ > h λ > 4 0 0 m

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µ = A? /A? = 0.5 {A? = 20 volt, A? = 40 volt}
m (t) = A? sin ω? t {ω? = 2π×10? }
c (t) = A? sin ω? t {ω? = 2π×10×10³}
C? (t) = (A? + A? sin ω? t) sin ω? t ⇒ A? {1+ µsin ω? t} sin ω? t

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Vishal Baghel

Kindly consider the following figure

V
Vishal Baghel

Amplitude of sidebands = µAc/2
Here µ = Am/Ac = 5/15 = 1/3
Amplitude = (1/3) (15)/2 = 2.5 V
a/10 = 2.5 => a = 25
b/10 = 2.5 => b = 25
a/b = 1

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